UTC 18:25:22 SAST 20:25 SFI 124 Kp 1 20 M GOOD 10 M FAIR 145.650 · 438.650 · 438.200 · 438.300 · 439.175
RAE practice questions

Chapter 18: The Transistor Amplifier

Free practice questions on The Transistor Amplifier, chapter 18 of the SARL's Class A manual, for South Africa's Radio Amateur Examination (RAE). Every question has the right answer and an explanation. Sections covered:

  • 18.1 Amplification
  • 18.2 Class C amplifiers
  • 18.3 The Class A common-emitter amplifier
  • 18.4 The common-collector (emitter-follower) amplifier
  • 18.5 The common-base amplifier
  • 18.6 The Class AB amplifier
  • 18.7 Field-effect transistors
  • 18.8 Thermionic tubes
  • 18.9 Integrated circuits

81 questions

  1. 1. Strictly speaking, what does an amplifier increase?
    Show answer

    The power of a signal

    Amplification means increasing a signal’s power, P = V × I, by raising the voltage, the current or both. A step-up transformer raises the voltage yet gives no amplification, because the current falls in step.

  2. 2. A stage delivers the same signal voltage as it receives, but 40 times the signal current. What is its power gain?
    Show answer

    40

    Power is V × I, so with the voltage unchanged and the current 40 times larger the power gain is 1 × 40 = 40. Unity voltage gain does not mean there is no amplification.

  3. 3. An ideal step-up transformer turns a signal of 3 V at 40 mA into 12 V. What is its power gain?
    Show answer

    1

    The input is 3 V × 40 mA = 120 mW, and an ideal transformer delivers the same 120 mW, now at 12 V and 10 mA: a power gain of 1. Its voltage ratio of 4 is not amplification.

    Try it: Ohm's Law & Power
  4. 4. A receiver must bring a signal of −110 dBm at its antenna up to +10 dBm. By what factor must the signal power rise?
    Show answer

    10¹²

    From −110 dBm to +10 dBm is 120 dB, and each 10 dB is a factor of 10 in power, so the factor is 10¹². Stopping at 0 dBm gives only 110 dB, 10¹¹.

    Try it: dBm, Watts & dB
  5. 5. Why is a practical receiver’s total gain often more than it needs to lift its weakest signals to about 1 mW?
    Show answer

    To make up for losses in parts such as filters

    Some stages, such as filters, lose part of the signal, so the receiver’s total gain must exceed the bare 10¹³ or so needed, to make up for them. Gain itself does not make a receiver more selective.

  6. 6. Why is the manual’s simple RF amplifier called a common-emitter amplifier?
    Show answer

    Its emitter is part of both the input and output circuits

    The input goes to the base and the output comes from the collector, so the emitter belongs to both circuits. The stage has one transistor; common means shared by input and output, not by two transistors.

  7. 7. In the manual’s simple RF amplifier, what does the inductor between the +12 V line and the collector do?
    Show answer

    It passes DC but blocks the RF signal

    The inductor passes DC, so the collector is biased positive and supply current can flow in, while its reactance blocks RF. Passing RF and blocking DC is the output capacitor’s job.

    Try it: Reactance & Resonance
  8. 8. In the manual’s simple RF amplifier, what does the capacitor between the collector and the output do?
    Show answer

    It passes the amplified AC on but blocks the DC

    The output capacitor passes the AC signal but blocks the collector’s DC, so the bias does not upset the next stage. It is in series with the output, not part of a tuned circuit.

  9. 9. In the manual’s simple RF amplifier, where does the power delivered to the output come from?
    Show answer

    From the DC supply that feeds the stage

    Power cannot be made from nothing: the small input only controls a larger current drawn from the DC supply, in the manual’s circuit the +12 V line via the inductor. The input itself supplies little power.

  10. 10. A sine wave of 0,4 V peak is applied straight to the base of an unbiased class C stage like the manual’s. What output results?
    Show answer

    None: the transistor never conducts

    A silicon transistor needs about 600 mV across its base-emitter junction before it conducts, and 0,4 V never gets there, so no collector current flows. Class C needs a large input signal.

  11. 11. A class C stage like the manual’s runs from a 13,8 V supply. Roughly how high can its collector voltage rise as the transistor switches off?
    Show answer

    27,6 V

    As the transistor switches off, the inductor keeps its current flowing and drives the collector above the supply, by the manual up to about twice it: 2 × 13,8 = 27,6 V. It is not capped at 13,8 V.

  12. 12. In a class C stage like the manual’s, what happens to the collector voltage as the transistor turns on and conducts?
    Show answer

    It drops below the supply voltage

    Collector current through the inductor makes it develop a voltage that pulls the collector below the supply. The collector rises above the supply only when the transistor switches off again.

  13. 13. For what part of each input cycle does the transistor in a class C amplifier conduct?
    Show answer

    Less than half of it, under 180°

    Class C conducts for under half of each cycle, less than 180°: in the manual’s stage only while the input is above about 600 mV. Exactly half, 180°, is class B; the full cycle is class A.

  14. 14. Which use does the manual give for class C amplifiers?
    Show answer

    The RF power stage of CW and FM transmitters

    Class C distorts badly but is efficient, which suits CW and FM power stages, where a lowpass filter removes the harmonics. Amplifying an SSB signal needs a linear amplifier, which class C is not.

  15. 15. The manual says class C stages are unsuitable for amplifying AM and SSB signals. What kind of amplifier do such signals need?
    Show answer

    A linear amplifier

    AM and SSB signals must keep their exact shape, so they need a linear amplifier that reproduces the waveform faithfully, such as class A or a good class AB stage. More gain cannot cure distortion.

  16. 16. Why does the distortion of a class C stage matter little in a CW or FM transmitter?
    Show answer

    A lowpass filter after the stage easily removes its harmonics

    Distortion creates harmonics at multiples of the wanted frequency, above it, so a lowpass filter after the stage removes them easily. A highpass filter would pass the harmonics and block the signal.

    Try it: Low-pass Filter Designer
  17. 17. What efficiency does the manual say is common for class C amplifiers?
    Show answer

    60 to 70%

    In class C most of the supply power reaches the output; the manual calls 60 to 70% common. About 25% is its figure for class A, which wastes power on a constant bias current.

  18. 18. An amplifier stage draws 50 W from its DC supply and delivers 41 W to its load. Which option is nearest to its efficiency?
    Show answer

    80%

    Efficiency is output ÷ DC input = 41 ÷ 50 = 0,82, or 82%, so 80% is nearest. The 9 W lost is heat in the transistor; 18% is that wasted share, not the efficiency.

  19. 19. The bias and drive of a transistor amplifier are set so that base current flows throughout every cycle of the input. In which class is it working?
    Show answer

    Class A

    A transistor that conducts for the whole cycle, 360°, is working in class A, as in the manual’s biased common-emitter stage. Class AB conducts for more than half the cycle but not all of it.

  20. 20. In a class A stage like the manual’s, R1 = 33 kΩ runs from a 9 V supply to the base and R2 = 12 kΩ from the base to 0 V. Ignoring the base current, what is the base voltage?
    Show answer

    2,4 V

    VB = 9 V × R2 ÷ (R1 + R2) = 9 × 12 ÷ 45 = 2,4 V. Working it over R1 gives 6,6 V, which is the drop across R1, not the voltage on the base.

    Try it: Voltage Divider
  21. 21. A class A stage has R1 = 82 kΩ from its 12 V supply to the base and R2 = 18 kΩ from the base to 0 V. Ignoring the base current, which option is nearest to the base voltage?
    Show answer

    2,2 V

    VB = 12 V × 18 ÷ (82 + 18) = 2,16 V, so 2,2 V is nearest. Putting R1 in the top of the fraction gives 9,84 V, the drop across R1, nearest the 10 V option.

    Try it: Voltage Divider
  22. 22. The base of a class A stage like the manual’s is biased to 2,6 V, and its emitter resistor is 1 kΩ. Roughly what emitter current flows in the silicon transistor?
    Show answer

    2 mA

    The emitter sits about 0,6 V below the base, at 2,6 − 0,6 = 2,0 V, so IE = 2,0 V ÷ 1 kΩ = 2 mA. Forgetting the base-emitter drop gives 2,6 mA.

    Try it: Ohm's Law & Power
  23. 23. In a class A stage, the bias sets the emitter current at 1,5 mA, and the transistor’s β is 149. What is the base current?
    Show answer

    10 µA

    The emitter carries IB + IC = IB + 149 IB = 150 IB, so IB = 1,5 mA ÷ 150 = 10 µA. The 1,49 mA is the collector’s share, the other 149 parts in 150.

  24. 24. In a class A stage like the manual’s, the bias holds the emitter current at 1 mA. Its transistor, with a β of 100, is replaced by one with a β of 500. What happens to the collector current?
    Show answer

    It rises by under 1%, so barely changes

    IC = IE × β ÷ (β + 1): 1 mA × 100 ÷ 101 = 990 µA, and with β = 500 about 998 µA, under 1% more. The bias, not β, sets the current, so IC ≈ IE.

  25. 25. In a class A stage like the manual’s, the bias resistors are R1 = 15 kΩ and R2 = 10 kΩ. Neglecting the transistor itself, what input impedance does the signal see?
    Show answer

    6 kΩ

    The supply is at AC ground, so R1 and R2 appear in parallel: 15 × 10 ÷ (15 + 10) = 6 kΩ. Adding them as if in series gives 25 kΩ, the DC path through the divider.

    Try it: Components: Colour Codes & Values
  26. 26. The bias resistors of a class A stage are R1 = 56 kΩ and R2 = 8,2 kΩ. Neglecting the transistor itself, which option is nearest to the input impedance the signal sees?
    Show answer

    7 kΩ

    R1 and R2 act in parallel for the signal: 56 × 8,2 ÷ (56 + 8,2) = 7,15 kΩ, so 7 kΩ is nearest. Adding them in series gives 64,2 kΩ, nearest the 65 kΩ option.

    Try it: Components: Colour Codes & Values
  27. 27. Why does an input signal see the bias resistors R1 and R2 of the manual’s class A stage as if they were in parallel?
    Show answer

    The supply line is held at AC ground by the decoupling capacitor

    Decoupling capacitor C3 gives the supply line an AC path to the chassis, so for the signal the top of R1 is grounded, like the bottom of R2. C1 only couples the signal to the base.

  28. 28. A class A common-emitter stage like the manual’s has RE = 470 Ω and a load RL = 8,2 kΩ. Using the manual’s formula, which option is nearest to its voltage gain?
    Show answer

    17

    Voltage gain = RL ÷ RE = 8 200 ÷ 470 = 17,4, so 17 is nearest. Squaring it gives about 300, which is the power gain (with equal input and load resistances), not the voltage gain.

  29. 29. A class A stage has a voltage gain of 20, and its load resistance equals its input resistance. What is its power gain in decibels?
    Show answer

    26 dB

    With equal resistances the power gain is the voltage gain squared, 20² = 400, and 10 log 400 = 26 dB. Taking 10 log of the voltage gain alone gives only 13 dB.

    Try it: dBm, Watts & dB
  30. 30. What kinds of gain can a common-emitter amplifier provide, according to the manual?
    Show answer

    Both voltage gain and current gain

    A common-emitter stage can raise both the voltage and the current of a signal, so its power gain is large. Current gain without voltage gain describes the emitter follower, whose voltage gain is about 1.

  31. 31. In a class A stage like the manual’s, the base is biased at +3,2 V. How large a peak input can it take before the emitter current of its silicon transistor drops to zero on the negative peaks?
    Show answer

    2,6 V

    The emitter sits at 3,2 − 0,6 = 2,6 V, so the input can swing 2,6 V negative before the emitter reaches 0 V and conduction stops. Forgetting the base-emitter drop gives 3,2 V.

  32. 32. An amplifier takes 10 W from its DC supply and delivers 2 W to its load. What is its efficiency?
    Show answer

    20%

    Efficiency = power to the load ÷ power from the supply = 2 ÷ 10 = 20%. The other 8 W, 80% of the input, ends up as heat in the transistor.

  33. 33. Roughly what efficiency does the manual give for a typical class A amplifier?
    Show answer

    About 25%

    The constant bias current wastes power, so typically only about a quarter of the supply power reaches the load and the rest heats the transistor. 60 to 70% is the manual’s class C figure.

  34. 34. Why does the manual say that almost all small-signal amplifiers can be class A?
    Show answer

    So little power is involved that the waste is unimportant

    Class A wastes much of its supply power, but a small-signal stage handles so little power that the waste is unimportant, and class A copies the waveform faithfully. It draws the most idle current, not the least.

  35. 35. How does the manual describe the output impedance of its class A common-emitter stage?
    Show answer

    Quite high, like a current source

    Collector current is set by the base and hardly depends on collector voltage, so the collector behaves as a current source of fairly high impedance; L1 also has high reactance. Low output impedance is the emitter follower’s.

  36. 36. Why is the common-collector amplifier also known as an emitter follower?
    Show answer

    Its emitter voltage follows its base voltage

    Its output comes from the emitter, which stays about 0,6 V below the base and so rises and falls with it, giving a voltage gain of about 1. The collector is the common terminal, fixed at the supply.

  37. 37. The signal at the base of a common-collector amplifier swings by 1,8 V peak to peak. Roughly what peak-to-peak swing appears at its emitter?
    Show answer

    1,8 V

    A change at the base gives an equal change at the emitter: the voltage gain is about 1, so the 1,8 V swing comes through whole. The 0,6 V drop is a fixed DC offset, not taken off the swing.

  38. 38. What sort of output impedance does an emitter follower have?
    Show answer

    Low, so its output voltage barely changes with load

    An emitter follower’s output impedance is fairly low, so it acts as a good voltage source whose output hardly depends on the load. High output impedance, a current source, belongs to the common-emitter and common-base stages.

  39. 39. What sort of input impedance does an emitter follower present to the stage that drives it?
    Show answer

    High, so it draws little from that stage

    An emitter follower’s input impedance is high, so it draws little from the stage before it; that, with its low output impedance, makes it a good buffer. Low input impedance is the common-base stage’s.

  40. 40. Which job does the manual suggest for an emitter follower?
    Show answer

    A buffer, so later stages do not upset earlier ones

    With high input and low output impedance, an emitter follower makes a good buffer: changes in the stages after it do not reach the stage before it. Its voltage gain is only about 1.

  41. 41. The base of an emitter follower sits at +5,0 V DC, and its silicon transistor is conducting. What DC voltage is on its emitter?
    Show answer

    4,4 V

    A conducting silicon transistor keeps its emitter about 0,6 V below its base: 5,0 − 0,6 = 4,4 V. The emitter follows changes at the base, but always about 0,6 V lower.

  42. 42. When can an emitter follower provide power gain, according to the manual?
    Show answer

    When it delivers more current than it takes from its source

    Its voltage gain is only about 1, but power is V × I, so it gives power gain whenever its output current exceeds its input current, which it easily does. Drawing more current than it delivers would be a loss.

  43. 43. What input impedance does the manual give for a common-base amplifier?
    Show answer

    Very low, a few ohms or tens of ohms

    The common-base input is very low: the manual says typically only a few ohms, and in practice it is about 25 Ω at 1 mA of emitter current. High input impedance is the emitter follower’s.

  44. 44. What output impedance does a common-base amplifier have?
    Show answer

    High, many kilohms or more

    Like the common emitter, the common-base stage has a high output impedance, making it a good current source. A low output impedance and good voltage source describe the emitter follower.

  45. 45. What current gain does the manual give for a common-base amplifier?
    Show answer

    One: its output current equals its input current

    The common-base stage has a current gain of one, which is why the manual calls it a current follower; in practice it is just under 1. A current gain of about β belongs to the other two configurations.

  46. 46. When can a common-base stage provide power gain?
    Show answer

    When its load resistance is greater than its input impedance

    With unity current gain the same current flows in and out, so by P = I²R the power rises in proportion to resistance: a load larger than the input impedance gives power gain. The reverse gives a loss.

  47. 47. A common-base stage has an input impedance of 25 Ω and drives a 5 kΩ load, with the same signal current in both. What is its power gain?
    Show answer

    200

    With equal currents, P = I²R makes the power gain the ratio of the resistances: 5 000 ÷ 25 = 200, about 23 dB. Unity current gain does not rule out power gain.

    Try it: Ohm's Law & Power
  48. 48. How common is the common-base configuration, compared with the other two?
    Show answer

    Less widely used than the other two

    The manual calls common base the third and less common configuration, behind common emitter and common collector, though it has its uses as a current follower. It is an amplifier, not a rectifier.

  49. 49. An amplifier’s output device conducts for about 230° of every 360° input cycle. In which class is it working?
    Show answer

    Class AB

    Between 180° and 360° is class AB: each device is biased slightly on, so it conducts for a little over half the cycle (the manual says about 180°). Exactly 180° is class B, the full 360° class A.

  50. 50. For what part of the input cycle does the device in a class B amplifier conduct?
    Show answer

    Exactly half of it, 180°

    Class B conducts for exactly half the cycle, 180°, and the manual notes it is not commonly used. A little more than half, between 180° and 360°, is class AB.

  51. 51. In the manual’s class AB circuit, what does the bias voltage VBias do when there is no input signal?
    Show answer

    It keeps a small current flowing in both transistors

    VBias is just enough to keep both transistors conducting a little with no input, so neither starts from fully off; this reduces crossover distortion. Holding them fully off would be class B behaviour.

  52. 52. The bias of an RF power amplifier sets its conduction angle at 360°. Which statement about it is true?
    Show answer

    Its device never cuts off at any point in the cycle

    A conduction angle of 360° means conduction for the whole cycle, class A: bias current keeps the device from ever cutting off. That constant current makes class A the least efficient class, not the most.

  53. 53. Which amplifier class reproduces the shape of its input waveform with the least distortion?
    Show answer

    Class A

    Class A conducts for the whole cycle, so it copies the waveform faithfully with little distortion. Class AB comes next but adds some crossover distortion; class C distorts heavily.

  54. 54. In a push-pull class AB stage, what is the distortion called that occurs at the moment one device stops and the other starts conducting?
    Show answer

    Crossover distortion

    Crossover distortion appears where one device stops conducting and the other takes over; good design keeps it within reasonable limits. Clipping is the flattening of peaks when a stage is overdriven.

  55. 55. In the manual’s class AB circuit, what does the transformer at the input do?
    Show answer

    It feeds the bases in opposite phase

    The input transformer is a phase splitter: its two halves drive the bases 180° out of phase, so one transistor conducts harder as the other turns off. Adding the collector signals is the output transformer’s job.

  56. 56. In the manual’s class AB circuit, what does the transformer at the output do?
    Show answer

    It adds the two collector signals together

    Each transistor handles about half of each cycle, and the output transformer adds the two collector signals back together, so the output has both half cycles. Feeding the bases in opposite phase is the input transformer’s job.

  57. 57. Which statement about a well-designed class AB power amplifier agrees with the manual?
    Show answer

    It suits AM and SSB signals as a power stage

    Class AB is much more efficient than class A and much more linear than class C, so it suits AM and SSB power amplifiers. Being too nonlinear to amplify AM signals is class C’s failing.

  58. 58. Which amplifier class can reach the highest efficiency?
    Show answer

    Class C

    Class C conducts for only part of each cycle, so little power is wasted, and the manual calls 60 to 70% efficiency common. Class AB beats class A but cannot match class C.

  59. 59. What is the main way in which a field-effect transistor differs from a bipolar junction transistor?
    Show answer

    It is controlled by a voltage rather than a current

    A FET is controlled by the voltage on its gate, which draws almost no current, while a bipolar transistor needs base current. The close option describes the bipolar transistor instead.

  60. 60. When a bipolar transistor circuit is rebuilt with FETs, why may some of its bias networks need redesigning?
    Show answer

    FETs need voltage bias rather than current bias

    A FET’s gate takes a bias voltage and draws almost no current, so networks designed to feed a base current may need changing. It is the bipolar transistor that needs bias current.

  61. 61. When a FET replaces a bipolar transistor, which of its terminals takes the place of the collector?
    Show answer

    The drain

    In general the gate replaces the base, the drain the collector and the source the emitter. Emitter and base are bipolar transistor terminals, which a FET does not have.

  62. 62. What are the three electrodes of a field-effect transistor called?
    Show answer

    Gate, source and drain

    A FET’s electrodes are the gate, the source and the drain; a voltage on the gate controls the drain-source channel. Base, emitter and collector are the bipolar transistor’s names.

  63. 63. What is the FET counterpart of the bipolar emitter follower called?
    Show answer

    The source follower

    The source takes the emitter’s place, so the emitter follower becomes the source follower, also called common drain. The drain stands in for the collector, so a drain follower is no emitter-follower counterpart.

  64. 64. Why are FETs the usual choice for logic and computer chips?
    Show answer

    Large-scale integration makes them cheaper to produce

    Making MOS devices costs less and goes more smoothly in large-scale integration, so FETs dominate logic and computer chips. They are still made of doped semiconductor, like junction transistors.

  65. 65. In which field does the manual say MOSFETs have almost completely displaced junction transistors?
    Show answer

    Switching at high power levels

    MOSFETs are now everywhere in high-power switching, where they have almost completely displaced junction transistors; the manual’s summary also names logic and RF power amplifiers. It makes no such claim for small-signal audio.

  66. 66. What do the names N-channel and P-channel describe in a FET?
    Show answer

    The doping of its channel: N-type or P-type

    FETs come in two basic types, named after the semiconductor type of the drain-source channel: N-type or P-type. The supply polarity follows from the type but does not name it.

  67. 67. In MOS technology, what provides the insulation between the structures of a FET?
    Show answer

    An extremely thin layer of oxide

    MOS means metal-oxide semiconductor: an ultra-thin oxide insulates the structures (the manual names aluminium oxide; silicon dioxide is the classic choice). A forward-biased PN junction conducts, so it cannot insulate.

  68. 68. In which amateur radio application do tubes still survive, according to the manual?
    Show answer

    RF power amplifiers of 1 kW and above

    Semiconductors have largely replaced tubes, but tubes survive in high-power RF work such as linear amplifiers of 1 kW and above, and are robust enough for home-built amplifiers. Receiver front ends use semiconductors.

  69. 69. Why are tubes still popular in some high-end audio and guitar amplifiers?
    Show answer

    Their harmonic distortion pleases some listeners

    Tubes distort differently from solid-state devices, and some listeners find their kind of harmonic distortion more pleasing. They do distort; the difference is in the character of the distortion.

  70. 70. In a thermionic tube, which electrode gives off electrons when it is heated?
    Show answer

    The cathode

    The heated cathode emits electrons, which form a cloud around it; the anode (plate in American usage) collects them when it is positive. The anode receives electrons rather than giving them off.

  71. 71. When will a current flow between the electrodes of a thermionic diode?
    Show answer

    When its anode is positive relative to its cathode

    A positive anode attracts the electrons given off by the heated cathode, so current flows. With the anode negative relative to the cathode the electrons are repelled, and no current flows.

  72. 72. In a triode, what does a small change in grid voltage control?
    Show answer

    The amount of anode current

    The grid sits between cathode and anode, and a small change in its voltage controls how much current reaches the anode, much as a gate voltage controls a FET. It does not heat the cathode.

  73. 73. What name is given to the release of electrons by a heated cathode?
    Show answer

    Thermionic emission

    Heating gives the cathode’s electrons enough energy to escape, forming a cloud around it: thermionic emission, which gives the tubes their name. Photoelectric emission is driven by light, not heat.

  74. 74. Why are discrete components seldom used in modern electronics?
    Show answer

    ICs do the same job in less space, at lower cost

    One IC can hold thousands, millions or more components on a tiny chip of silicon, far smaller and cheaper than the same circuit built from discrete parts. High power is where discrete parts still win.

  75. 75. What does Moore’s law describe?
    Show answer

    Twice as many transistors fitting on a chip about every two years

    Moore’s law, named after Gordon Moore, is that twice as many transistors fit on a chip about every two years; the manual puts it as ICs shrinking by half. Chips get denser, not bigger.

  76. 76. How can a small microprocessor board be made to do a different job?
    Show answer

    By writing new software for it

    Its microprocessor simply follows its software, so new software turns the same board to a new task, which makes such boards so handy for amateur projects. No hardware needs changing.

  77. 77. Which product ranges does the manual recommend as bases for amateur radio projects?
    Show answer

    Arduino and Raspberry Pi

    Arduino and Raspberry Pi boards carry a reconfigurable processor with its ports brought out for easy connection. The LM741 is an op-amp and SOIC a package style, not project platforms.

  78. 78. Which set of properties does the manual give for a typical op-amp?
    Show answer

    High input impedance, low output impedance and high gain

    An op-amp offers high gain and linearity with little power drawn, taking almost nothing from its source (high input impedance) and driving loads easily (low output impedance). Swapped impedances suit neither job.

  79. 79. What does an op-amp amplify?
    Show answer

    The difference between the voltages at V+ and V−

    An op-amp’s output is an amplified copy of the difference between its V+ and V− inputs, and either input may be grounded. Adding the two input voltages is not what it does.

  80. 80. To which pins of an op-amp is its power supply connected?
    Show answer

    VS+ and VS−

    The supply goes to VS+ and VS−, for example +5 V and −5 V, or one of them may be grounded. V+ and V− are the signal inputs.

  81. 81. With a few outside resistors and capacitors, what can an op-amp be made into?
    Show answer

    Amplifiers, active filters and oscillators

    With simple networks of outside passive parts, an op-amp can make almost any signal amplifier, buffer, filter or signal generator (oscillator). Oscillators are well within its reach.