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RAE practice questions

Chapter 28: Electromagnetic Compatibility

Free practice questions on Electromagnetic Compatibility, chapter 28 of the SARL's Class A manual, for South Africa's Radio Amateur Examination (RAE). Every question has the right answer and an explanation. Sections covered:

  • 28.1 Definition of electromagnetic compatibility
  • 28.2 Intentional and unintentional radiators
  • 28.3 Interference to non-receiving equipment
  • 28.4 Intentional radiators interfering with receivers
  • 28.5 Shared bands
  • 28.6 Causes of interference
  • 28.7 Transmitter defects
  • 28.8 Receiver defects
  • 28.9 Common-mode chokes
  • 28.10 Direct radiation and shielding
  • 28.11 Sensible measures against interference

92 questions

  1. 1. Electromagnetic compatibility (EMC) is about electronic equipment being compatible with what?
    Show answer

    The man-made electromagnetic noise around it

    EMC is about devices sharing an environment full of man-made electromagnetic noise: keeping what each radiates down and its immunity up. It is not limited to natural static such as lightning.

  2. 2. Which of these is one aim of electromagnetic compatibility (EMC)?
    Show answer

    To cut the electrical noise polluting the radio spectrum

    EMC works on both sides: less noise generated by devices and more immunity to it, easing the electromagnetic smog of cities. It sets limits rather than demanding zero radiation, and sharing out bands is frequency allocation.

  3. 3. The manual sees two sides to every interference problem. Which does it call the harder one?
    Show answer

    Deciding who is responsible for solving it

    The technical side, the causes and the cures, is the easier one; the legal and social question of who must fix it is harder, because a legal approach often brings unwanted social results.

  4. 4. The manual classifies interference cases by the source and by the device affected. What does it ask about each?
    Show answer

    Whether the source must radiate, and whether the device is a receiver

    Sources are intentional radiators (transmitters) or unintentional ones (fences, ignition), and affected devices are receivers or not, like a hi-fi playing CDs; these, not power or distance, decide who must act.

  5. 5. A car’s spark ignition system interferes with radio reception. In the manual’s terms, what is the ignition system?
    Show answer

    An unintentional radiator

    The ignition system radiates although it does not need to in order to work, so it is an unintentional radiator, held to strict radiation limits. Intentional radiators, such as transmitters and garage remotes, must radiate.

  6. 6. Your reception suffers from noise coming from the electric fence next door. What does the manual say should happen?
    Show answer

    Its owner must fix it and keep it off until it complies

    A fence need not radiate, so strict limits apply; if it interferes it is probably over them, and its owner must have it repaired and keep it off until it complies. Filters at your end are not your duty.

    Try it: QRM Hunting
  7. 7. Which of these is a typical source of the electrical interference heard in towns?
    Show answer

    Switch contacts that spark as they break heavy currents

    A switch that makes or breaks a heavy current may spark, sending out a burst of noise that can travel a long way. Fibre carries light, not RF currents, so it radiates nothing.

    Try it: QRM Hunting
  8. 8. According to the manual, what is the combined effect of the millions of switches in a city?
    Show answer

    They slowly raise the noise level, hampering radio across the city

    Each switch adds a little noise, and millions of them raise the urban noise level until radio communication across the city is hampered. Random bursts of noise add up; they do not cancel.

  9. 9. Your transmissions are heard on a neighbour’s hi-fi while it plays CDs. Where does the manual place the fault?
    Show answer

    With the hi-fi, which should not respond to radio signals

    A hi-fi playing CDs is not meant to receive radio, so if it responds to RF the fault is in its design, not in your licensed transmitter: the hi-fi’s makers did not design it for strong fields.

  10. 10. What does the manual say about the sale of audio equipment that has never been tested near strong RF signals?
    Show answer

    It is legal, and works where only weak signals reach it

    Such equipment may legally be sold, and it works in about 99% of locations, which see only weak, distant signals. The trouble starts when a licensed amateur sets up next door.

  11. 11. Which word does the manual advise you to avoid when you discuss a problem with your neighbours?
    Show answer

    Radiation

    Though technically correct, the word radiation calls up ionising radiation and nuclear warning signs, and alarms people. Interference is a neutral word that describes the problem without frightening anyone.

  12. 12. Why does the manual advise offering your technical help to a neighbour whose hi-fi picks up your signals?
    Show answer

    Goodwill: the neighbour may have a say in your tower plans

    Curing it is the neighbour’s job, but helping is diplomatic: it keeps good relations, and the same neighbour may later be asked for comment when you apply to put up a tower. No licence condition requires it.

  13. 13. Your signal is inside an amateur band, within your power limit and clean, yet it upsets a neighbour’s TV. What does the manual conclude?
    Show answer

    The TV is faulty: it responds to a signal outside its band

    When the transmission is legal in every respect (in band, within power, clean), the receiving equipment is the defective part: it reacts to a signal outside its band, and its owner must have it repaired.

  14. 14. A neighbour reports interference from your station to ICASA, the regulator. What will ICASA probably do first?
    Show answer

    Inspect your transmitting equipment

    ICASA will probably check the transmitter first: if it is faulty or does not comply with your licence, you may be held responsible and it can be confiscated. So check your own signal before blaming the TV.

  15. 15. Your station is fully legal. A neighbour whose TV suffers refuses your offer of help and insists that you stop. What does the manual say?
    Show answer

    You are entitled to carry on operating

    Offering help is good diplomacy and good for amateur radio’s name, but if it is refused and you are sure your equipment is legal, you may keep operating despite the interference.

  16. 16. You solder a filter into a neighbour’s speaker leads to cure breakthrough. What risk does the manual warn about?
    Show answer

    Later faults in the system may be blamed on you

    Any change you make to a neighbour’s installation may be blamed for later trouble: if the sound system fails months afterwards, fingers will point at you. A filter at their speakers does nothing to your signal.

  17. 17. On what basis does the manual say amateurs hold the 13 cm band, and who has priority there?
    Show answer

    Secondary; industrial, scientific and medical users are primary

    Amateurs hold 13 cm as secondary users, and industrial, scientific and medical (ISM) use is primary. So amateurs must not interfere with ISM users and must accept interference from them.

    Try it: Band Plans
  18. 18. Medical equipment in a hospital next door, radiating on purpose in a band where amateurs are secondary users, interferes with your reception. What can you do, by the manual?
    Show answer

    Nothing: you must put up with it

    A secondary user has to put up with interference from the primary user, and must not cause it any, stopping if that is the only way. A complaint against a primary user working as intended would fail.

  19. 19. Which frequency range does the manual give for the 13 cm amateur band?
    Show answer

    2,3 to 2,45 GHz

    λ = 300 ÷ F gives 300 ÷ 2 300 = 0,13 m, hence the name 13 cm; the band runs from 2,3 to 2,45 GHz. 1,24 to 1,3 GHz is the 23 cm band.

    Try it: Band Plans
  20. 20. Every amateur band is shared with fellow amateurs. What does the manual say this calls for?
    Show answer

    Operating courtesy and a clean transmitted signal

    Every band is shared with fellow amateurs, so avoid interfering with them: operate with courtesy and keep your signal clean. No licence class has priority, and there is no rota or booking.

  21. 21. An amateur signal drifts until it lies just outside the band, where another service’s receiver picks it up. Which of the manual’s causes of interference is this?
    Show answer

    A transmitter radiating where it should not

    The transmitter is putting out energy where it should not, the manual’s first cause, so the cure is at the transmitter. The other service’s receiver is working on its own frequency, as it should.

  22. 22. A transmitter and a nearby receiver both work properly, yet harmonics of the signal are heard. What example does the manual give of how this can happen?
    Show answer

    A corroded gutter rectifying it and re-radiating harmonics

    Corrosion can make a metal joint act like a rectifier, a non-linear device, turning a strong nearby signal into harmonics that it re-radiates; this cause is rare and hard to trace. Absorption creates no new frequencies.

    Try it: QRM Hunting
  23. 23. Two signals pass together through any non-linear device. What will appear at its output?
    Show answer

    Mixing products: sums, differences, harmonics

    A non-linear device distorts the waveform, creating harmonics and sum and difference frequencies, as in a mixer (chapter 20); corroded joints do the same. A linear amplifier would only make the signals bigger.

  24. 24. The manual goes on to treat only transmitter faults and receiver faults in detail. Why does it leave its other main cause aside?
    Show answer

    It is uncommon and needs special equipment and expertise

    In the third cause something else, such as a corroded joint, converts the signal; it is quite uncommon, and tracing it usually takes special equipment and expertise. It is not the electricity supplier’s concern.

  25. 25. What does the manual give as the usual cause of frequency instability in a transmitter?
    Show answer

    Temperature and knocks affecting an LC oscillator

    LC oscillators drift as the temperature changes and shift when knocked, so they need temperature compensation and solid construction. Crystal oscillators are very stable, which is why crystal-controlled synthesisers seldom drift.

  26. 26. The PLL synthesiser in a transceiver loses lock to its reference. What happens to its output frequency?
    Show answer

    It is no longer held steady and may wander

    A synthesiser is only as stable as the reference it is locked to; once unlocked, its VCO runs free and is unstable. The crystal steadies the output only through the locked loop.

  27. 27. Chirp is a CW transmitter’s frequency shifting each time it is keyed. Which cure does the manual give?
    Show answer

    A high-impedance buffer stage following the oscillator

    Chirp comes from the keyed stages loading the oscillator, or its supply sagging, at each key-down; a buffer amplifier isolates the oscillator, and a regulated supply helps too. No filter can remove a frequency shift.

  28. 28. A transmitter on 145,6 MHz interferes with a UHF television receiver tuned near 582,4 MHz. Which harmonic is to blame?
    Show answer

    The fourth

    582,4 ÷ 145,6 = 4, so it is the fourth harmonic, found as in the manual’s 144 × 5 = 720 MHz example. The fifth would fall on 5 × 145,6 = 728 MHz.

    Try it: QRM Hunting
  29. 29. A 40 m transmitter works on 7,1 MHz. On what frequency is its second harmonic, and in which band does it fall?
    Show answer

    14,2 MHz, in the 20 m band

    The second harmonic is twice the fundamental: 2 × 7,1 = 14,2 MHz, inside the 20 m band (14,000 to 14,350 MHz). 21,3 MHz is the third harmonic, 3 × 7,1.

    Try it: Band Plans
  30. 30. A 70 cm operator hears a signal on 435,6 MHz that turns out to be the third harmonic of a local 2 m station. On what frequency is the 2 m station?
    Show answer

    145,2 MHz

    A harmonic is a whole multiple of the fundamental, so the station is on 435,6 ÷ 3 = 145,2 MHz, in the 2 m band. Multiplying by 3 instead (1 306,8 MHz) mixes up a harmonic and a sub-harmonic.

    Try it: Frequency ↔ Wavelength
  31. 31. You transmit on 50,4 MHz, and a neighbour’s FM radio picks you up only when it is tuned near 100,8 MHz. What is the most likely cause?
    Show answer

    The second harmonic of your signal

    100,8 ÷ 50,4 = 2: your second harmonic lands on that FM channel, a transmitter fault to cure at your end. Overload would spoil reception across the band, not at one spot.

    Try it: QRM Hunting
  32. 32. When does the manual recommend adding an extra lowpass filter between a transmitter and its antenna to cure harmonics?
    Show answer

    When harmonics remain with the drive set correctly

    Harmonics that come and go with the mic gain or CW drive mean the amplifier is overdriven, and the cure is less drive. Only if they persist when it is driven correctly is an extra lowpass filter the best cure.

    Try it: Low-pass Filter Designer
  33. 33. What does almost every HF transmitter have at its output to keep its harmonic radiation low?
    Show answer

    A lowpass filter

    Harmonics lie above the wanted frequency, so a lowpass filter after the final amplifier passes the signal and weakens them, typically by 50 dB or more at 50 MHz for HF filters. A highpass filter would pass the harmonics.

    Try it: Low-pass Filter Designer
  34. 34. The manual suggests leaving an ATU in line to help cut harmonics, even when no matching is needed. Which ATU circuit suits this?
    Show answer

    A Pi network with one inductor

    The ATU must work as a lowpass filter: a Pi network with one series coil, or a T with two series coils. The common T with two series capacitors is a highpass circuit and lets harmonics through.

    Try it: Low-pass Filter Designer
  35. 35. An amplifier with tuned circuits breaks into oscillation at their resonant frequency. What usually causes this?
    Show answer

    Some of its output finding its way back to its input

    Oscillation needs a loop: unintended feedback from the output back to the input of an amplifier with tuned circuits makes it oscillate at their resonance (self-oscillation). Input leaking forward to the output forms no loop.

  36. 36. Some of an amplifier’s output is reaching its input and making it oscillate. Which cure does the manual give?
    Show answer

    Negative feedback, to bring the loop gain down

    Negative feedback lowers the loop gain below what oscillation needs; cutting the coupling, say with shorter component leads, also works. Positive feedback is what makes an amplifier oscillate.

  37. 37. With no drive applied at all, an 18 MHz linear amplifier is found putting out a signal on about 18,1 MHz. What is this fault called?
    Show answer

    Self-oscillation

    Oscillation on or close to the working frequency, caused by feedback through the tuned circuits, is self-oscillation. Parasitic oscillations usually occur at VHF or UHF, far from the working frequency.

  38. 38. A 7,05 MHz amplifier also gives out a strong signal on 152,3 MHz. What is this signal most likely to be?
    Show answer

    A parasitic oscillation

    152,3 ÷ 7,05 = 21,6, not a whole number, so it is no harmonic; an unrelated VHF signal is typical of a parasitic oscillation from a hidden resonance. Self-oscillation would be near 7,05 MHz.

  39. 39. Unwanted oscillations can come from RF chokes resonating with decoupling capacitors. Which kind of RF choke makes them less likely?
    Show answer

    A low-Q, lossy choke

    A lossy, low-Q choke damps any hidden resonance so that it cannot sustain a parasitic oscillation; ferrite beads do a similar job. A high-Q choke makes a sharper resonance and oscillation more likely.

  40. 40. Which of these is most likely to stop a small transistor output stage from breaking into parasitic oscillation?
    Show answer

    A ferrite bead on a lead of the transistor

    A bead on the transistor’s emitter or base lead adds inductance and loss at VHF, right where the parasitic runs, damping it without affecting the working frequency. A bead on the microphone lead is nowhere near it.

  41. 41. What does a ferrite bead slipped over a wire do?
    Show answer

    It adds RF impedance, blocking RF but not DC

    The ferrite adds inductance and loss at RF, so RF on the wire is blocked or damped while DC passes freely; that is how beads stop VHF parasitics. A bead is not a screen like a coax braid.

  42. 42. Ferrite beads are fitted on the DC supply leads where those leads enter an RF power amplifier’s output tank circuit. What do the beads do there?
    Show answer

    They keep RF out of the DC wiring, while passing the DC

    Each bead adds series inductance at RF, and with its decoupling capacitor makes a little lowpass filter: DC reaches the stage, but RF is kept out of the supply wiring, where it could couple elsewhere.

  43. 43. An operator turns up the drive until an SSB linear amplifier is working well beyond its rating. What will other stations most likely notice?
    Show answer

    Splatter caused by intermodulation products

    Driven too hard, a linear amplifier flattens the peaks, and the speech frequencies mix into intermodulation products close to the signal, widening it into splatter. Harmonics appear too, but far away, where the output filter deals with them.

  44. 44. What is the trouble with a transmitter that causes splatter?
    Show answer

    Its signal is far wider than it needs to be

    Splatter is excessive bandwidth: the signal spreads onto neighbouring frequencies, usually through overdriving or overmodulation. Harmonics fall far away, on whole multiples of the frequency, and are a separate problem.

  45. 45. What is the highest modulation depth an AM transmitter should use, to avoid causing interference on adjacent channels?
    Show answer

    100%

    100% is the limit: the carrier just reaches zero at the troughs; beyond it the carrier cuts off and the distortion splatters onto adjacent channels. The manual’s 80% is only an example.

  46. 46. To keep a voice transmission from spreading onto adjacent channels, below about what frequency should its audio be kept?
    Show answer

    3 kHz

    Communications-quality speech needs only about 300 Hz to 3 kHz; audio above that just widens the signal and interferes with others, the price of chasing fidelity. 6 kHz is an AM signal’s whole bandwidth, both sidebands.

  47. 47. On most modern transmitters, how does the manual say the microphone gain should be set?
    Show answer

    So that the ALC reading stays within its marked range

    The ALC voltage shows how hard the transmitter is being driven; keeping it inside the range marked on the meter means no stage is overdriven. Chasing the highest power reading overdrives it and widens the signal.

  48. 48. How should a CW transmitter switch its carrier on and off, to avoid key clicks?
    Show answer

    Smoothly, over about 5 ms each way

    Keying the carrier abruptly spreads it into clicks either side of the signal; shaping each edge over about 5 ms keeps it narrow. Half a second would smear the Morse beyond reading.

  49. 49. A key wired straight into a high-power stage arcs at its contacts. What does the manual recommend?
    Show answer

    Key a low-power stage, or use a transistor or relay

    Keying a lower-power stage, or letting a transistor or relay do the switching, keeps the heavy current and voltage off the key. Bigger contacts would still spark at the same voltage and current.

  50. 50. Mains hum is heard on your transmitted signal, and the power supply is to blame. Which change should cure it?
    Show answer

    More smoothing capacitance, or a voltage regulator

    Hum is 100 Hz ripple left on the DC; a large smoothing capacitor (thousands of µF) or a regulator removes it. Small RF bypass capacitors have far too little capacitance to matter at 100 Hz.

  51. 51. Why does a station using a long wire worked against earth need a good RF earth?
    Show answer

    To keep RF voltages off the equipment and feedline

    With the earth as half of the antenna system, a good, separate RF earth carries the RF return, so that the equipment and feedline do not sit at RF voltages. Protection from mains faults is the mains earth’s job.

  52. 52. How should the lead from a station to its RF earth be run?
    Show answer

    As short and as direct as possible

    An earth lead has inductance, so every extra centimetre and every turn raises its impedance at RF: keep it short and straight. Coiling the spare length makes an inductor, the opposite of what is wanted.

  53. 53. Your HF station runs from a battery and gives no trouble until you connect a mains-powered computer, earthed through its plug, to the radio. Now a neighbour’s mains-powered alarm reacts to your signal. What is the most likely cause?
    Show answer

    The mains earth has become part of a poor RF earth path

    Mains-earthed equipment lets station RF flow on the mains earth, which runs beside live and neutral, couples into them and carries RF to neighbouring buildings. The cure is a good separate RF earth; harmonics are not the issue.

  54. 54. Even where a good separate RF earth is used, why must the equipment still be connected to the mains earth?
    Show answer

    So that a fault does not leave a lethal voltage on its case

    The mains earth is a safety earth: it carries fault current so the case cannot become live. It often has a high impedance at RF and runs beside live and neutral, so it is a poor and troublesome RF path.

  55. 55. An SSB transmitter’s balanced modulator is out of balance, so some carrier leaks through. What will listeners most likely notice?
    Show answer

    A steady heterodyne whistle along with the speech

    An SSB signal should carry no carrier; a leftover carrier beats with the receiver’s BFO or with other signals, giving a steady tone (a heterodyne) on the audio. Wrong pitch comes from mistuning the receiver.

  56. 56. Receiver overload is the most common receiver defect behind interference from amateur stations. How does it produce the interference?
    Show answer

    Intermodulation in the first mixer creates spurious signals

    A signal stronger than the receiver was designed for drives the first mixer into non-linearity, and intermodulation creates spurious products that land among the wanted signals. An image is a separate defect, set by the tuning and the IF.

  57. 57. Why does the manual single out cheap masthead TV preamplifiers?
    Show answer

    They overload easily on strong signals

    Inexpensive masthead preamplifiers, used to improve TV reception in marginal areas, are very prone to overloading; models with good signal handling exist but cost more. Low gain is not their problem.

  58. 58. A TV system with a masthead preamplifier needs a filter to keep out a strong amateur signal. Where should the filter go?
    Show answer

    On the mast, ahead of the preamplifier

    The filter must stop the strong signal before it reaches the preamplifier, which would otherwise overload and make spurious products that no later filter can remove. A filter behind the set comes too late.

  59. 59. A cheap masthead preamplifier is being overloaded by a nearby amateur station. Why will a filter between the preamplifier and the TV NOT help?
    Show answer

    The products are already made in the preamplifier

    Once the preamplifier overloads, its spurious products fall inside the TV channels, so no filter after it can separate them, though a suitable filter would pass the TV signals. Replace or remove the preamplifier.

  60. 60. HF amateur signals are interfering with a neighbour’s TV through its antenna lead. Which filter at the TV does the manual suggest?
    Show answer

    A highpass filter in the TV’s antenna lead

    TV signals lie at VHF and UHF, well above HF, so a highpass filter passes them and blocks the HF signal. A lowpass filter would do the opposite, keeping the HF signal and blocking the TV channels.

    Try it: High-pass Filter Designer
  61. 61. Amateur 2 m signals are spoiling a neighbour’s UHF television picture. Which filter does the manual suggest might cure it?
    Show answer

    A highpass filter cutting off at 470 MHz

    UHF television starts at 470 MHz, above the 2 m band, so a highpass filter with that cutoff passes the TV channels and blocks the 144 MHz signal. A 100 MHz highpass would let 2 m straight through.

    Try it: High-pass Filter Designer
  62. 62. Amateur VHF transmissions reach a neighbour’s VHF television through its antenna and spoil the picture. Which filter does the manual say may be needed?
    Show answer

    A trap: a bandstop filter for that band

    With both signals at VHF, a highpass filter is unlikely to separate them, so a bandstop filter (a trap) for the interfering amateur band is needed. A choke stops currents on the braid, not signals arriving through the antenna.

  63. 63. In interference work, what does a trap do?
    Show answer

    It blocks one band of frequencies and passes those either side

    A trap is a bandstop or notch filter: it removes a band of frequencies, such as one interfering amateur band, while passing those above and below. Passing only one band is what a bandpass filter does.

  64. 64. A length of feedline, open at its far end and a quarter wavelength long at one interfering VHF frequency, is connected across a TV downlead to remove that frequency. What is it called?
    Show answer

    A stub

    A quarter-wave length of line connected across a feeder is a stub; open at the far end, it shorts the feeder at the frequency where it is exactly a quarter wave. A phasing line joins antenna elements.

  65. 65. How long should an open-ended coaxial stub be, to short out an interfering signal on a feedline?
    Show answer

    A quarter wavelength of that signal, measured in the cable

    The stub must be a quarter wavelength at the interfering frequency, and as waves travel more slowly in coax, that is the free-space length times the velocity factor. Cut to the free-space length it would resonate too low.

  66. 66. An open-ended coax stub with a velocity factor of 0,66 is to short out 145 MHz signals on a TV downlead. Which option is nearest to its length?
    Show answer

    35 cm

    λ = 300 ÷ 145 = 2,07 m; a quarter is 0,517 m, and in coax 0,517 × 0,66 = 0,341 m, nearest 35 cm. Forgetting the velocity factor gives the free-space 52 cm.

    Try it: Frequency ↔ Wavelength
  67. 67. A medium-wave receiver with a 455 kHz IF, its local oscillator above the signal, is tuned to a station on 1 040 kHz. On which frequency would a strong signal cause image (second-channel) interference?
    Show answer

    1 950 kHz

    The LO is at 1 040 + 455 = 1 495 kHz, and the image one IF above it, at 1 950 kHz, in the 160 m band. 1 495 kHz, f + IF, is the LO itself.

    Try it: Frequency ↔ Wavelength
  68. 68. A VHF scanner with a 10,7 MHz IF, its local oscillator above the signal, suffers image interference from a 2 m transmitter on 145,0 MHz. To which frequency is the scanner tuned?
    Show answer

    123,6 MHz

    With the LO above the signal, the image lies two IFs above the tuned frequency, so the scanner is on 145,0 − 21,4 = 123,6 MHz. Subtracting one IF (134,3 MHz) gives the LO, not the tuned frequency.

    Try it: Frequency ↔ Wavelength
  69. 69. A loud nearby station sounds ‘wide’, with interference on the channels either side of it. You switch in your receiver’s 20 dB attenuator, and that interference drops by 40 dB or more. Where is the problem?
    Show answer

    In your own receiver, which was overloaded

    Interference made in the transmitter would fall by only the attenuator’s 20 dB, like the signal; a drop of 40 dB or more means your receiver was making it through overload. Then the attenuator is a cure.

  70. 70. Switching in the attenuator or turning off the preamplifier cures some interference. What does the manual say you give up, and what improves?
    Show answer

    Sensitivity is lost, but the signal-to-noise ratio improves

    Any cut in signal level costs sensitivity, but with the receiver no longer overloaded the interference falls further than the wanted signal, so the signal-to-noise ratio improves. Selectivity is set by the filters.

  71. 71. In common-mode interference, how does the unwanted signal travel along a two-conductor lead?
    Show answer

    In the same direction, in phase, on both conductors

    Common-mode signals flow the same way, in phase, on both conductors: live and neutral, both speaker wires, or a coax inner and its braid. Opposite currents are differential, like the wanted signal in a TV downlead.

  72. 72. Which currents does a common-mode choke let through unaffected?
    Show answer

    Currents flowing opposite ways in the two conductors

    The wanted signal’s currents run opposite ways in the two conductors, so their magnetic fields cancel and it passes unaffected; currents flowing the same way in both are common-mode and meet the choke’s inductance.

  73. 73. Why does a common-mode choke leave the wanted signal in a TV antenna lead unaffected?
    Show answer

    Its opposite currents’ fields cancel in the core

    In the wanted, differential signal the two currents flow in opposite directions, so their magnetic fields cancel and the core sees no net field; the choke is then no inductor to it. A weak signal would still meet the inductance.

  74. 74. How is a common-mode choke usually made?
    Show answer

    Turns of the cable itself on a ferrite ring

    Turns of the mains, speaker or coax cable on a ferrite toroid form an inductor for common-mode current; despite the name braid breaker, nothing is cut. A capacitor across the conductors would act on the wanted signal.

    Try it: DIY Baluns & Ununs
  75. 75. A neighbour’s TV picks up HF amateur signals that travel along the outside of its downlead’s screen. Which cure does the manual point to?
    Show answer

    A braid breaker fitted to the downlead

    Current on the outside of the screen is common-mode, flowing the same way on inner and braid, so a common-mode choke on the downlead (a braid breaker) stops it before it reaches the set. A bead elsewhere misses its path.

  76. 76. A nearby 2 m transmitter induces signals on the braid of the long downlead to a neighbour’s FM radio. What is the best cure to try?
    Show answer

    A braid breaker fitted near the radio

    Signals induced on the braid travel as common-mode current, which a toroidal choke (braid breaker) on the downlead blocks; a filter at the socket acts only on the differential signal inside. More power makes it worse.

  77. 77. A common-mode choke works well against common-mode interference at 28 MHz but barely helps at 3,5 MHz. What would most likely help?
    Show answer

    More turns on its core, to raise its inductance

    A choke rejects a signal only if its impedance at that frequency is high enough, and XL = 2πfL falls with frequency; more turns, or a better core, raise L. Fewer turns would make it worse.

    Try it: Coils & Toroids
  78. 78. Common-mode chokes can be fitted to the leads of which kinds of equipment?
    Show answer

    Receivers such as TV sets, and also audio amplifiers

    A common-mode choke works on any lead that carries interference in, so it suits TV sets and radios and also equipment that is not a receiver at all, like an audio amplifier troubled by strong signals.

  79. 79. A choke has an inductance of 30 µH. Which option is nearest to its reactance at 7,05 MHz?
    Show answer

    1,3 kΩ

    XL = 2πfL = 6,283 × 7,05 × 30 = 1 329 Ω (megahertz times microhenry gives ohms), nearest 1,3 kΩ. Leaving out the 2π gives 7,05 × 30 = 212 Ω.

    Try it: Coils & Toroids
  80. 80. Strong signals from a nearby high-power antenna couple straight into a TV set’s IF stages. How does this show itself?
    Show answer

    The interference shows on every channel the set receives

    Every channel passes through the same IF stages, so a signal coupled straight into them is present whatever channel is chosen. Interference on one channel points instead to a harmonic or an image landing there.

  81. 81. A field strength meter can measure the two fields of an electromagnetic wave. In which units are they given?
    Show answer

    E in V/m, and H in A/m

    The electric field E is given in V/m and the magnetic field H in A/m, and a field strength meter reads them. Swapping them confuses the electric field (voltage) with the magnetic field (current).

  82. 82. Besides shielding, which remedy does the manual give for strong fields coupling straight into a circuit?
    Show answer

    Good design, using decoupling capacitors

    Direct pickup bypasses the leads, so the cure lies in the circuit itself: good design with decoupling components, as well as a shield around it. Beads on the leads stop only what travels along the wires.

  83. 83. Whenever the station transmits, strong RF from a nearby HF antenna gets straight into the circuits of a desktop computer. What is the simplest effective cure, according to the manual?
    Show answer

    A Faraday cage: a conductive box that encloses it

    At HF and above the coupling is mainly by the electric field, which any conductive enclosure (a Faraday cage) keeps out. Thick Mu Metal also works but is far harder to use; it is needed only for mainly magnetic coupling.

  84. 84. A screening box has ventilation holes about 10 cm in circumference. Signals at which frequency are most likely to get in through them?
    Show answer

    About 1,3 GHz

    Holes pass signals whose wavelength is not much longer than their circumference: at 1,3 GHz, λ = 300 ÷ 1 300 = 0,23 m, about twice 10 cm; at 145 MHz and below it is over 20 times as long.

    Try it: Frequency ↔ Wavelength
  85. 85. What does the manual say about shielding against coupling that is mainly magnetic?
    Show answer

    Thick shields of special metals, such as Mu Metal

    Electric fields are easily stopped by any conductive box, but magnetic coupling needs relatively thick shields of special materials such as Mu Metal or Permalloy. Luckily, magnetic fields are seldom the main problem at HF and above.

  86. 86. Some transmitters radiate energy that never passes through the antenna socket. What is this called, and how is it cured?
    Show answer

    Cabinet radiation, cured by better screening

    Stray currents inside a badly designed cabinet radiate directly, bypassing the antenna socket and any filter there; the cure is better screening, a Faraday cage round the transmitter. Matching the antenna does nothing for it.

  87. 87. Which feeder is least likely to radiate and cause interference itself?
    Show answer

    Screened cable with its screen properly earthed

    The earthed screen keeps the RF inside the cable, so the feeder itself neither radiates nor picks up much: shielding works both ways. An unscreened feeder radiates, whatever its length.

  88. 88. Besides its main job, what else does the manual say a good shield around a device does?
    Show answer

    It cuts the noise the equipment itself radiates

    Shielding works in both directions: a conductive enclosure that keeps strong fields out also keeps the device’s own noise in, reducing objectionable radiation. It does nothing for wanted reception through an antenna.

  89. 89. By the manual’s sensible measures, where should an amateur antenna be put?
    Show answer

    Where it gives the weakest field in nearby homes

    Interference falls off with distance, so the antenna should go where it gives the lowest field strength in homes, its own and the neighbours’: high, and as far from them as possible. Hiding it low often does the opposite.

  90. 90. An amateur in a townhouse complex can put a new HF beam on a 5 m or a 15 m mast, either at the far end of the garden or right beside the neighbour’s house. Which choice keeps interference to the neighbours lowest?
    Show answer

    The 15 m mast at the far end of the garden

    Field strength falls with distance, so the far end helps, and height lifts the strongest field over nearby houses instead of through them: the 15 m mast there does both. A low mast puts the beam nearer everyone’s wiring.

  91. 91. How should the feeder from an amateur antenna be routed through the house?
    Show answer

    On its own route, well clear of other cables

    Running the feeder clear of mains, telephone and TV cables keeps it from coupling RF into them, where it would travel to other equipment. Bundling it with the TV downlead invites exactly that.

  92. 92. Which of these does the manual list among the simple courtesies that prevent much interference?
    Show answer

    Using the least power the contact needs

    The manual’s simple rules are: antennas high and far from others, the minimum power the contact needs, and listening before transmitting. Full power raises the field strength in every nearby home.