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RAE practice questions

Chapter 8: Alternating Current

Free practice questions on Alternating Current, chapter 8 of the SARL's Class A manual, for South Africa's Radio Amateur Examination (RAE). Every question has the right answer and an explanation. Sections covered:

  • 8.1 Introduction
  • 8.2 The sine signal
  • 8.3 Cycles and half-cycles
  • 8.4 Period and frequency
  • 8.5 Wavelength and the speed of light
  • 8.6 Phase
  • 8.7 RMS voltage and current
  • 8.8 Frequency ranges

80 questions

  1. 1. Why does the current in a DC circuit always flow the same way round?
    Show answer

    One terminal of the source stays positive

    A DC source keeps its polarity: the same terminal is always the positive one, so the current flows one way only. Its size may still vary: the fixed polarity, not a steady voltage, keeps the current one way.

  2. 2. What do the abbreviations AC and DC stand for?
    Show answer

    Alternating current and direct current

    AC is alternating current, which reverses its direction at regular intervals, and DC is direct current, which always flows the same way. Both name a current, not a charge.

  3. 3. May the abbreviation AC also be used to describe a voltage?
    Show answer

    Yes, as on a winding marked '12 V AC'

    Although AC strictly means alternating current, the abbreviation is used for voltages that alternate too, as in '12 V AC' or 'an AC voltage'. Keeping it for currents only is not how the term is used.

  4. 4. A sine signal can be pictured with a point on the rim of a wheel turning at a steady speed. Which quantity traces out the sine?
    Show answer

    The point's height above or below the axle

    The height a of the rim point above or below the axle rises and falls as the sine of the angle, one cycle per full turn of 360°. The angle itself grows steadily: it is the graph's horizontal axis.

  5. 5. A rim point of a wheel of radius r has turned through an angle Ø, measured from the horizontal. Which expression gives its height a above the axle?
    Show answer

    a = r sin Ø

    From sin Ø = a ÷ r, the height is a = r sin Ø, which is why the curve is called a sine function. r cos Ø is the sideways distance of the point from the axle, not its height.

  6. 6. A sine signal has a peak value of 16 V; sin 30° = 0,5 and cos 30° = 0,866. What is its value 30° after it passes through zero, rising?
    Show answer

    8 V

    V = VPeak × sin Ø, VPeak being the peak, the highest value reached: 16 × 0,5 = 8 V. Using cos 30° = 0,866 by mistake gives 16 × 0,866 = 13,9 V.

  7. 7. Which angle gives a sine signal the same value as it has at 140°?
    Show answer

    40°

    The sine peaks at 90° and falls back as a mirror image of its rise, so 140° matches 180° − 140° = 40°. 50° is only how far 140° lies past the peak, and at 220° the value is negative.

  8. 8. A 250 Hz sine signal passes through zero, rising. How long does it take to reach its positive peak?
    Show answer

    1 ms

    The period is 1 ÷ 250 = 4 ms, and the peak comes a quarter cycle (90°) after the rising zero crossing: 1 ms. At 2 ms, half a cycle, it is back at zero; 0,64 ms comes from 2πft = 1.

    Try it: Frequency ↔ Wavelength
  9. 9. A sketch shows a sine signal drawn as two half-circles, one above the line and one below. Is it a true picture of a sine?
    Show answer

    No, a sine curve is not made of half-circles

    The manual warns that a sine is often wrongly drawn as two semicircles. Its true shape follows a = r sin Ø: it crosses the line at a slant, where half-circles would stand straight up.

  10. 10. Why are AC circuits normally analysed using sine signals?
    Show answer

    Any periodic waveform can be built from sines

    Fourier showed that any periodic signal is a sum of sines of different frequencies, so a circuit's response to sines gives its response to any waveform (Fourier analysis), not only to the mains.

  11. 11. A test oscillator's output holds the fundamental frequency alone, with no harmonics at all. What shape is its waveform?
    Show answer

    A sine signal

    Only a sine signal is pure, a single frequency: the fundamental. A triangular signal looks smooth but still holds harmonics, whole-number multiples of the fundamental, as square, pulse and sawtooth signals do.

  12. 12. What are the harmonics of a signal?
    Show answer

    Whole-number multiples of the fundamental

    Harmonics lie at whole-number multiples of the fundamental f: 2f, 3f, 4f and so on. Fractions such as f ÷ 2 are not harmonics, and a pure sine signal has no harmonics at all.

  13. 13. A transmitter works on 3,7 MHz. What is the frequency of its third harmonic?
    Show answer

    11,1 MHz

    The third harmonic is three times the fundamental: 3 × 3,7 = 11,1 MHz. 7,4 MHz is only 2 × 3,7, the second harmonic, and dividing by three gives no harmonic at all.

  14. 14. In the manual's formula for the voltage of a sine signal, what does the letter t stand for?
    Show answer

    The time, from a rising zero crossing

    In V = VPeak sin (2πft), t is the time since the sine passed through zero going positive, and f is the frequency. It is not the period, which the manual also writes as t.

  15. 15. Over time, what is a sine signal made up of?
    Show answer

    Identical cycles, repeated again and again

    An AC signal is a string of identical cycles, each a copy of the one before. That is why it has one period and one frequency: every cycle takes the same time.

  16. 16. What is the part of a sine signal above zero called?
    Show answer

    The positive half-cycle

    Each cycle has a positive half-cycle, above zero, and a negative half-cycle below it; a whole cycle holds both. The positive peak is only the highest point of the positive half-cycle.

  17. 17. For what part of each cycle is a sine signal positive?
    Show answer

    Half of each cycle

    A sine signal is positive for the first half of each cycle, 0° to 180°, and negative for the second half. A quarter of a cycle only takes it from zero up to its positive peak.

  18. 18. How many times does a sine signal pass through zero in each complete cycle?
    Show answer

    Twice

    A sine crosses zero going down at 180°, where the positive half-cycle ends, and going up at 360°, where the next begins: twice per cycle. At the peaks, 90° and 270°, it turns back without reaching zero.

  19. 19. What is one hertz (1 Hz)?
    Show answer

    One cycle per second

    Frequency counts the cycles completed each second, and its unit, the hertz, is one cycle per second. One second per cycle describes a period, the time of each cycle, which is measured in seconds.

  20. 20. What is the period of a waveform?
    Show answer

    The time taken by one complete cycle

    The period is the time of one complete cycle, from any point to the matching point of the next cycle, given in s, ms or µs. The signal is positive for only half of that time.

    Try it: Frequency ↔ Wavelength
  21. 21. A waveform completes 720 cycles in 0,4 s. What is its frequency?
    Show answer

    1,8 kHz

    Frequency is cycles per second: 720 ÷ 0,4 = 1800 Hz = 1,8 kHz. Multiplying, 720 × 0,4 = 288, means nothing, and 0,4 ÷ 720 = 556 µs is the time of one cycle, the period.

    Try it: Frequency ↔ Wavelength
  22. 22. A complete cycle of a waveform is to be marked out. Where may it start?
    Show answer

    At any point, ending at the next matching point

    A cycle may start at any point, a zero crossing, a peak or a value in between, and runs to the corresponding point of the next cycle. Starting at a zero crossing is merely convenient.

  23. 23. What is the period of a 16 Hz signal?
    Show answer

    62,5 ms

    t = 1 ÷ f = 1 ÷ 16 = 0,0625 s = 62,5 ms. 6,25 ms slips a power of ten: 1 s is 1000 ms, so 0,0625 s is 62,5 ms.

    Try it: Frequency ↔ Wavelength
  24. 24. A waveform has a period of 40 µs. What is its frequency?
    Show answer

    25 kHz

    f = 1 ÷ t = 1 ÷ 0,000 04 s = 25 000 Hz = 25 kHz. 2,5 kHz is a power of ten out: it is the frequency of a signal whose period is 400 µs.

    Try it: Frequency ↔ Wavelength
  25. 25. What is the period of a 4 MHz signal?
    Show answer

    0,25 µs

    t = 1 ÷ f = 1 ÷ 4 000 000 = 0,000 000 25 s = 0,25 µs, or 250 ns. 2,5 µs is ten times too long: it is the period of a 400 kHz signal.

    Try it: Frequency ↔ Wavelength
  26. 26. A signal has a period of 0,7 µs. Which is nearest to its frequency?
    Show answer

    1,4 MHz

    f = 1 ÷ t = 1 ÷ 0,000 000 7 s = 1 428 571 Hz, about 1,43 MHz, nearest 1,4 MHz. 14 MHz is a power of ten out: it needs a period of only 0,07 µs.

    Try it: Frequency ↔ Wavelength
  27. 27. What is the period of an 800 Hz tone?
    Show answer

    1,25 ms

    t = 1 ÷ f = 1 ÷ 800 = 0,001 25 s = 1,25 ms. 12,5 ms is ten times too long: it is the period of an 80 Hz tone, a tenth of the frequency.

    Try it: Frequency ↔ Wavelength
  28. 28. What is the frequency of the mains supply in South Africa?
    Show answer

    50 Hz

    South African mains runs at 50 Hz, so each cycle lasts 1 ÷ 50 = 20 ms. 60 Hz is the mains frequency of North America and some other countries, not of South Africa.

  29. 29. What is the period of a 50 kHz signal?
    Show answer

    20 µs

    t = 1 ÷ f = 1 ÷ 50 000 = 0,000 02 s = 20 µs. 2 µs is ten times too short: it is the period of a 500 kHz signal.

    Try it: Frequency ↔ Wavelength
  30. 30. What is the wavelength of a wave?
    Show answer

    The distance it travels during one cycle

    The wavelength is the distance the wave covers in one complete cycle, so λ = c × t, the speed of light times the period. From a positive peak to the next negative peak is only half a wavelength.

    Try it: Frequency ↔ Wavelength
  31. 31. A radio signal's period is 4 µs. What is its free-space wavelength?
    Show answer

    1200 m

    λ = c × t = 3 × 10⁸ m/s × 4 × 10⁻⁶ s = 1200 m: the wave covers one wavelength in each period. Taking c as 3 × 10⁷ m/s, a power of ten short, gives 120 m.

    Try it: Frequency ↔ Wavelength
  32. 32. Why do radio amateurs usually work out wavelengths with the frequency in megahertz, rather than in hertz?
    Show answer

    It avoids handling powers of ten

    With F in megahertz the zeros cancel: c = 300 000 000 m/s, so λ = c ÷ f becomes λ = 300 ÷ F. The two give exactly the same answer; neither is more accurate.

    Try it: Constants & Rules of Thumb
  33. 33. What is the free-space wavelength of a 60 MHz signal?
    Show answer

    5 m

    λ = 300 ÷ F = 300 ÷ 60 = 5 m, with F in MHz. 50 m is a power of ten out: it is the wavelength of a 6 MHz signal.

    Try it: Frequency ↔ Wavelength
  34. 34. What is the wavelength of a 7,1 MHz signal?
    Show answer

    42,3 m

    λ = 300 ÷ F = 300 ÷ 7,1 = 42,3 m, which is why 7,1 MHz lies in the 40 m band. 4,23 m has the decimal comma one place out, a power of ten.

    Try it: Frequency ↔ Wavelength
  35. 35. Which is nearest to the wavelength of a 433 MHz signal?
    Show answer

    69 cm

    λ = 300 ÷ F = 300 ÷ 433 = 0,693 m, nearest 69 cm, inside the 70 cm band. 6,9 cm is a power of ten out, and 433 ÷ 300 = 1,44 turns the formula upside down.

    Try it: Frequency ↔ Wavelength
  36. 36. Which frequency has a free-space wavelength of 80 m?
    Show answer

    3,75 MHz

    F = 300 ÷ λ = 300 ÷ 80 = 3,75 MHz, in the 80 m band. 37,5 MHz is a power of ten out: its wavelength would be 8 m.

    Try it: Frequency ↔ Wavelength
  37. 37. A medium-wave broadcast station transmits on 702 kHz. What is its wavelength?
    Show answer

    427 m

    λ = c ÷ f = 300 000 000 ÷ 702 000 = 427 m. Putting 702 into λ = 300 ÷ F gives 0,427 m, but the shortcut needs F in MHz, here 0,702 MHz.

    Try it: Frequency ↔ Wavelength
  38. 38. Which is nearest to the wavelength of an 18,1 MHz signal?
    Show answer

    17 m

    λ = 300 ÷ F = 300 ÷ 18,1 = 16,6 m, nearest 17 m, inside the 17 m band. 1,7 m has the decimal comma one place out, a power of ten.

    Try it: Frequency ↔ Wavelength
  39. 39. Which is nearest to the frequency of a signal whose wavelength is 13 cm?
    Show answer

    2,3 GHz

    F = 300 ÷ λ = 300 ÷ 0,13 = 2308 MHz, nearest 2,3 GHz, with λ in metres. Taking 13 cm as 1,3 m gives 230 MHz, a power of ten too low.

    Try it: Frequency ↔ Wavelength
  40. 40. What is the wavelength of a 1,2 MHz signal?
    Show answer

    250 m

    λ = 300 ÷ F = 300 ÷ 1,2 = 250 m. 25 m is ten times too short: it is the wavelength of a 12 MHz signal. 360 m multiplies instead of dividing.

    Try it: Frequency ↔ Wavelength
  41. 41. Which frequency has a free-space wavelength of 15 m?
    Show answer

    20 MHz

    F = 300 ÷ λ = 300 ÷ 15 = 20 MHz, with λ in metres. 2 MHz is a power of ten out: its wavelength is 150 m. 300 × 15 = 4500 MHz multiplies instead of dividing.

    Try it: Frequency ↔ Wavelength
  42. 42. A radio wave travels through free space for 5 ms. How far does it go?
    Show answer

    1500 km

    Radio waves travel at the speed of light, c = 3 × 10⁸ m/s, so in 0,005 s they cover 1 500 000 m = 1500 km. 1500 m is the distance for 5 µs, a thousand times shorter.

    Try it: Frequency ↔ Wavelength
  43. 43. Why is the amateur band that starts at 144 MHz called the two-metre band?
    Show answer

    The name is a handy label, not an exact wavelength

    At 144 MHz, λ = 300 ÷ 144 = 2,08 m, so 'two metres' is a convenient name rather than a precise wavelength. No rule rounds band names; the name is simply shorter than the exact figure.

    Try it: Frequency ↔ Wavelength
  44. 44. Between which frequencies does South Africa's two-metre amateur band lie?
    Show answer

    144 and 146 MHz

    In South Africa the two-metre band runs from 144 to 146 MHz, where λ is about 2,07 m. 144 to 148 MHz is the wider band of the Americas, not the South African one.

    Try it: Band Plans
  45. 45. Two sine signals of equal size and frequency are 180° apart. Where is the second when the first reaches its negative peak?
    Show answer

    At its positive peak

    180° is half a cycle, so the two signals are mirror images: when one is at its negative peak the other is at its positive peak. Passing through zero would mean they were 90° apart.

  46. 46. Signal A passes through zero, going positive, a third of a cycle before signal B does. Which statement is right?
    Show answer

    A leads B by 120°

    Signals of one frequency whose cycles begin at different moments have a phase difference. The one that gets there first leads, so A leads B; a third of a cycle is 360° ÷ 3 = 120°, not 33°.

  47. 47. Signal B lags signal A by 30°. What does this mean?
    Show answer

    B peaks a twelfth of a cycle after A

    Lagging means arriving later: B reaches its peak, and every other point of its cycle, after A; 30° is 30 ÷ 360 = a twelfth of a cycle. Peaking earlier would make B the leading signal.

  48. 48. When the phase of two signals is compared, which points on the waveforms should be used?
    Show answer

    Any point, if it is the matching point on both

    Any point can be used, a peak, a zero crossing or a value in between, as long as it is the corresponding point on both signals. Peaks and zero crossings are merely the easiest to see.

  49. 49. Two signals of the same frequency are one-eighth of a cycle apart. What is the phase difference between them?
    Show answer

    45°

    One cycle is 360°, so one-eighth of a cycle is 360 ÷ 8 = 45°. Taking a whole cycle as 180° gives 22,5°, but 180° is only half a cycle.

  50. 50. Two 2 kHz signals are compared, and B reaches each peak 0,1 ms after A. What is the phase difference?
    Show answer

    72°

    The period is 1 ÷ 2000 = 0,5 ms, so B is 0,1 ÷ 0,5 = 0,2 of a cycle later: 0,2 × 360° = 72°. Multiplying 0,1 by 360 without dividing by the period gives 36°.

    Try it: Frequency ↔ Wavelength
  51. 51. Signal X leads a reference by 85°, and signal Y leads the same reference by 25°. By how many degrees does X lead Y?
    Show answer

    60°

    Both phases are measured from the same reference, so subtract: 85° − 25° = 60°. Adding them, 110°, would be right only if Y lagged the reference by 25° instead of leading it.

  52. 52. Two 1,2 kHz signals are compared, and B reaches each peak 0,15 ms after A. Which is nearest to the phase difference?
    Show answer

    65°

    The period is 1 ÷ 1200 = 0,833 ms, so B is 0,15 ÷ 0,833 = 0,18 of a cycle later: 0,18 × 360° = 64,8°, nearest 65°. Multiplying 0,15 by 360 without the period gives 54°.

    Try it: Frequency ↔ Wavelength
  53. 53. Two 5 kHz signals are 18° apart. By how much time is one behind the other?
    Show answer

    10 µs

    One cycle lasts 1 ÷ 5000 = 0,2 ms = 200 µs, and 18° is 18 ÷ 360 = 0,05 of a cycle: 0,05 × 200 µs = 10 µs. 100 µs is a power of ten out.

    Try it: Frequency ↔ Wavelength
  54. 54. A sine voltage is applied to a resistor. At which points in each cycle is the power it dissipates greatest?
    Show answer

    At both the positive and the negative peaks

    P = V² ÷ R, and V² is largest at either peak, since squaring a negative voltage gives a positive number. At the zero crossings the power falls to zero.

  55. 55. Why does a resistor still heat up while the sine voltage across it is negative?
    Show answer

    V² is positive even when V is negative

    The power is P = V² ÷ R, and squaring a negative voltage gives a positive result, so the resistor is heated just as much while V is negative. No stored heat is needed to explain it.

  56. 56. What does RMS stand for?
    Show answer

    Root mean square

    RMS means root mean square: the square root of the mean (average) of the squared values over a cycle. It is named after squaring the values, not after the sine.

  57. 57. Which statement defines a sine voltage's RMS value?
    Show answer

    The steady voltage that heats a resistor equally

    The RMS value is the steady (DC) voltage that would make a resistance dissipate the same power. The average while the voltage is positive is another, smaller figure: 0,637 of the peak against 0,707.

  58. 58. Which value of a sine voltage gives a resistor the same heating as a battery of that voltage?
    Show answer

    Its RMS value

    By definition the RMS value heats a resistance just as a DC voltage of the same size would. The average of a sine over a cycle is zero, and its peak is 1,414 times the RMS value.

  59. 59. To get a sine signal's RMS value from its peak value, you multiply by what number?
    Show answer

    0,707

    VRMS = VPeak ÷ √2 = 0,707 × VPeak, since 1 ÷ √2 = 0,707. Multiplying by 1,414, which is √2, goes the other way: from the RMS value up to the peak.

  60. 60. A sine signal has a peak value of 50 V. What is the RMS value of the signal?
    Show answer

    35,4 V

    VRMS = 0,707 × VPeak = 0,707 × 50 = 35,4 V. Multiplying by 1,414 gives 70,7 V, but that turns an RMS value into a peak, the wrong way round here.

  61. 61. A transformer winding gives 18 V RMS. Which is nearest to its peak voltage?
    Show answer

    25 V

    VPeak = √2 × VRMS = 1,414 × 18 = 25,45 V, nearest 25 V. Multiplying by 0,707 instead gives 12,7 V, less than the RMS value, which a peak can never be.

  62. 62. For which waveforms does VRMS = 0,707 × VPeak hold?
    Show answer

    Sine signals only

    The 0,707 factor holds only for a sine signal; other waveforms have other ratios. A square signal, for one, has an RMS value equal to its peak value.

  63. 63. A 50 Ω dummy load dissipates 72 W from a sine signal. Which is nearest to the peak current through it?
    Show answer

    1,7 A

    IRMS = √(P ÷ R) = √(72 ÷ 50) = √1,44 = 1,2 A, and IPeak = 1,414 × 1,2 = 1,697 A, nearest 1,7 A. 1,2 A is the RMS current, which the power formula gives, not the peak.

    Try it: Ohm's Law & Power
  64. 64. A sine voltage is quoted simply as 24 V, with nothing else said. What kind of value is that taken to be?
    Show answer

    RMS

    Any AC figure without a label, voltage or current, is taken to be an RMS value, so 24 V means 24 V RMS. A peak value has to be labelled as one.

  65. 65. A 3,45 kW heater is fed from the 230 V mains. How much current flows?
    Show answer

    15 A RMS

    I = P ÷ V = 3450 ÷ 230 = 15 A. The 230 V is an RMS value, as AC figures are unless stated otherwise, so the 15 A is RMS too; its peak is 1,414 × 15 = 21,2 A.

    Try it: Ohm's Law & Power
  66. 66. A 40 V RMS sine voltage is connected across a 200 Ω resistor. What power does the resistor dissipate?
    Show answer

    8 W

    With RMS values the DC formula holds: P = V² ÷ R = 40² ÷ 200 = 1600 ÷ 200 = 8 W. Using the peak voltage, 56,6 V, doubles the answer to a wrong 16 W.

    Try it: Ohm's Law & Power
  67. 67. A 16 Ω speaker is fed a 25 W sine test tone. What RMS voltage is there across it?
    Show answer

    20 V

    V = √(P × R) = √(25 × 16) = √400 = 20 V, an RMS value, as the power formulas work in RMS. √(P ÷ R) = 1,25 gives the current in amperes, not the voltage.

    Try it: Ohm's Law & Power
  68. 68. A 12,6 V RMS transformer winding feeds a 33 Ω resistor. Which is nearest to the power it dissipates?
    Show answer

    4,8 W

    P = V² ÷ R = 12,6² ÷ 33 = 158,8 ÷ 33 = 4,81 W, nearest 4,8 W. Squaring the peak voltage, 17,8 V, instead of the RMS value doubles it to about 9,6 W.

    Try it: Ohm's Law & Power
  69. 69. A 30 V RMS sine voltage is across a 12 Ω resistor. What is the RMS current through it?
    Show answer

    2,5 A

    Ohm's Law holds with RMS values: I = V ÷ R = 30 ÷ 12 = 2,5 A RMS. 12 ÷ 30 = 0,4 divides the wrong way round, and 30² ÷ 12 = 75 is the power in watts, not a current.

    Try it: Ohm's Law & Power
  70. 70. A 36 W lamp runs from a 48 V RMS sine supply. What RMS current does it draw?
    Show answer

    0,75 A

    I = P ÷ V = 36 ÷ 48 = 0,75 A, an RMS current, as the power formulas work with RMS values. 1,06 A is the peak current, 1,414 times larger; 48 ÷ 36 = 1,33 divides the wrong way.

    Try it: Ohm's Law & Power
  71. 71. Which frequencies make up the HF (high frequency) range?
    Show answer

    3 MHz to 30 MHz

    HF runs from 3 to 30 MHz, wavelengths from 100 m down to 10 m, and holds the amateur bands from 80 m to 10 m. 30 to 300 MHz is VHF, the next range up.

  72. 72. Which frequencies make up the VHF range?
    Show answer

    30 MHz to 300 MHz

    VHF runs from 30 to 300 MHz, wavelengths 10 m down to 1 m, and includes the 6 m and 2 m bands. 300 MHz to 3 GHz is the next range up, UHF.

  73. 73. Which frequencies make up the UHF range?
    Show answer

    300 MHz to 3 GHz

    UHF runs from 300 MHz to 3 GHz, wavelengths 1 m down to 100 mm, and includes the 70 cm and 23 cm bands. 30 to 300 MHz is VHF, the range below it.

  74. 74. In which frequency range is the two-metre amateur band?
    Show answer

    VHF

    The 2 m band, about 300 ÷ 2 = 150 MHz, lies in VHF, 30 to 300 MHz, as does the 6 m band near 50 MHz. UHF begins only at 300 MHz.

    Try it: Frequency ↔ Wavelength
  75. 75. In which frequency range is the 160 m amateur band?
    Show answer

    MF

    300 ÷ 160 = 1,875 MHz, inside MF, 300 kHz to 3 MHz. HF begins only at 3 MHz, so the manual's table lists 160 m as the MF amateur band.

    Try it: Frequency ↔ Wavelength
  76. 76. Which frequency range contains a signal with a wavelength of 23 cm?
    Show answer

    UHF

    F = 300 ÷ λ = 300 ÷ 0,23 = 1304 MHz, about 1,3 GHz, between 300 MHz and 3 GHz: UHF, which also holds the 70 cm band. SHF starts only at 3 GHz.

    Try it: Frequency ↔ Wavelength
  77. 77. Which frequency range has wavelengths from 10 m down to 1 m?
    Show answer

    VHF

    VHF, 30 to 300 MHz, has wavelengths from 300 ÷ 30 = 10 m down to 300 ÷ 300 = 1 m. HF, 3 to 30 MHz, runs from 100 m down to 10 m, the range below.

    Try it: Frequency ↔ Wavelength
  78. 78. Why is one of the ranges called 'high frequency' (HF)?
    Show answer

    It counted as high when the names were chosen

    When the name 'high frequency' was given, these were among the highest frequencies in use; higher ranges were named later, and 'high' was kept for historical reasons. It describes the frequency, not how high the waves travel.

  79. 79. Which frequency ranges does the manual say most amateurs use, and so must know well?
    Show answer

    HF, VHF and perhaps UHF

    Most amateurs work on HF and VHF, and many on UHF as well, so these three ranges matter most. Leaving out HF, where most amateur bands lie, is wrong, and SHF is for the few.

  80. 80. In the name UHF, what does the U stand for?
    Show answer

    Ultra

    UHF is ultra-high frequency, 300 MHz to 3 GHz, the range above VHF, very high frequency. The table names its ranges low, medium, high, very, ultra, super, extremely and tremendously high.