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RAE practice questions

Chapter 30: Digital Systems

Free practice questions on Digital Systems, chapter 30 of the SARL's Class A manual, for South Africa's Radio Amateur Examination (RAE). Every question has the right answer and an explanation. Sections covered:

  • 30.1 Advantages of digital systems
  • 30.2 Principles of Digital Signal Processing
  • 30.3 Digital filters
  • 30.4 Direct digital synthesis
  • 30.5 The Fourier transform
  • 30.6 Convolution
  • 30.7 SDR platforms

84 questions

  1. 1. Which of these sets of qualities does the manual claim for digital circuits, compared with analogue ones?
    Show answer

    Smaller, cheaper and much of their work automated

    The manual lists digital circuits as smaller and therefore cheaper, free of sensitive adjustment, robust, largely automated and updatable by software. Lower power use is not among its claims.

  2. 2. How do digital circuits cope with rough handling, such as knocks and vibration, compared with analogue circuits?
    Show answer

    Better: they are more robust against it

    Robustness against abuse such as impact and vibration is one of the advantages the manual gives for digital circuits. Tiny parts do not make them fragile; analogue circuits with sensitive settings are more easily upset.

  3. 3. How can a digital radio be kept current for many years as new modes and new rules come along?
    Show answer

    Design changes can be loaded as software downloads

    Design changes can be made by downloading new software rather than modifying the hardware, so the set stays current for decades. Swapping boards is the physical modification that software downloads avoid.

  4. 4. What makes analogue circuits demand so much care, according to the manual?
    Show answer

    Their parts all vary slightly and drift as they age

    Capacitors, inductors, resistors and semiconductors all vary slightly and drift with time, so analogue circuits need care and adjustment. Drifting is not wearing out, and two-valued signals are digital, not analogue.

  5. 5. When does a digital circuit need sensitive adjustment, by the manual?
    Show answer

    At no stage, in manufacture or in use

    Among the advantages of digital circuits the manual lists that they need no sensitive adjustment, either while being made or while in use. A one-off factory alignment is typical of analogue equipment.

  6. 6. By the manual, what really sets digital radio systems apart from analogue ones?
    Show answer

    A computer’s sums do the work of mixers and amplifiers

    In a digital system, amplification, mixing, filtering, modulation and detection are done with numbers in a computer or DSP chip. Analogue radios use transistors and chips too, so that is no difference.

  7. 7. How does a digital signal processor do the job of a mixer?
    Show answer

    It multiplies the samples of the two signals together

    Mixing is multiplication (chapter 20), and a computer multiplies numbers easily, giving the same sum and difference products. Adding samples only superimposes the two signals and makes no new frequencies.

  8. 8. What lets a specialised DSP chip do its sums much faster than an ordinary microcomputer?
    Show answer

    Array processors working on thousands of numbers at once

    DSP chips use tricks such as dedicated array processors, which carry out thousands of multiplications or other operations at the same time. The speed does not come from a faster clock; desktop processors often clock faster.

  9. 9. What does the word ‘digital’ mean in the manual’s sense?
    Show answer

    Based on numbers, in separate steps

    ‘Digital’ means based on numbers, such as integers, with nothing between neighbouring values. A quantity that can take any value, with always another in between, is analogue; the finger is only where the word comes from.

  10. 10. A logic circuit reads anything below 2,5 V as 0 and anything above 2,5 V as 1. What does this gain?
    Show answer

    Noise and small errors no longer cause mistakes

    With only two states and a wide margin either side of 2,5 V, noise and small voltage errors do not change which symbol is read. Carrying just two symbols per wire is the whole point of binary.

  11. 11. What is the binary number 1011 0110₂ in decimal?
    Show answer

    182

    1011 0110₂ = 128 + 32 + 16 + 4 + 2 = 182, most significant bit on the left. Read from the wrong end it gives 109; 364 doubles every place value, and 198 is B6₁₆ with B taken as 12.

  12. 12. Which of these is the decimal number 45 written in binary?
    Show answer

    0010 1101₂

    32 + 8 + 4 + 1 = 45, so the 32, 8, 4 and 1 places hold a 1: 0010 1101₂. Written from the wrong end it gives 1011 0100₂ (180), and 1101 0010₂ has its two groups of four swapped.

  13. 13. What is 110,11₂ in decimal?
    Show answer

    6,75

    Bits after the comma are worth ½, ¼, ⅛ and so on, so 110,11₂ = 4 + 2 + 0,5 + 0,25 = 6,75. Reading the two bits after the comma as the whole number 3 gives the wrong 6,3.

  14. 14. What is 0xE9 in decimal?
    Show answer

    233

    0xE9 = 14 × 16 + 9 = 233, since the letters A to F stand for 10 to 15. Taking E as 15 gives 249, and using tens instead of sixteens gives 149.

  15. 15. Which of these is the decimal number 200 in hexadecimal?
    Show answer

    C8₁₆

    12 × 16 + 8 = 200, and 12 is written C, so 200 = C8₁₆. B stands for 11, so B8₁₆ is only 11 × 16 + 8 = 184.

  16. 16. Which of these is 1101 0011₂ in hexadecimal?
    Show answer

    D3₁₆

    Split the bits into groups of four: 1101 = 13 = D and 0011 = 3, giving D3₁₆. Reading 1101 backwards gives B by mistake, and 211 is the decimal value, not hexadecimal.

  17. 17. What is the decimal number 93 in BCD?
    Show answer

    1001 0011

    BCD codes each decimal digit in four bits: 9 = 1001 and 3 = 0011, giving 1001 0011. 0101 1101 is 93 as a plain binary number, which is a different code.

  18. 18. Which statement about BCD and hexadecimal words is right?
    Show answer

    A BCD word is not a true binary number; a hexadecimal one is

    Each four-bit group in BCD holds one decimal digit, so the word is not a true binary number and needs special handling for sums; hexadecimal is simply binary, four bits to a digit. The swap is the usual slip.

  19. 19. Which of these is NOT a valid hexadecimal number?
    Show answer

    0x7G4E

    Hexadecimal digits run from 0 to 9 and then A to F, so G cannot appear and 0x7G4E is invalid. FACE₁₆ looks odd but is valid, since it uses only the letters A to F.

  20. 20. In the manual’s terms, what is a word?
    Show answer

    Several bytes taken together

    A word is several bytes taken together; modern desktop machines mostly use 32-bit or 64-bit words, so no single size such as 16 bits fits every processor. A single binary digit is a bit.

  21. 21. What is a group of four bits called?
    Show answer

    A nibble

    Four bits make a nibble and eight bits a byte; several bytes together form a word. One hexadecimal digit stands for exactly one nibble.

  22. 22. What sets Boolean algebra apart from ordinary algebra?
    Show answer

    Its values are bits, and every result is a single bit as well

    Boolean values are bits, false or true, and every answer must be a bit too: 1 OR 1 gives 1. A carry into a second bit belongs to ordinary binary arithmetic, where 1 + 1 makes 10₂.

  23. 23. In Boolean algebra, as the manual writes it, what is A + 0?
    Show answer

    A

    In Boolean algebra + means OR, and anything OR false is itself, so A + 0 = A. Answering 0 confuses OR with AND, for which A ● 0 = 0.

  24. 24. In the manual’s notation for Boolean algebra, what is −0?
    Show answer

    1

    The manual writes NOT as a minus sign: −0 = 1 and −1 = 0, so NOT always flips the bit. In ordinary arithmetic minus zero is zero, but that rule does not apply to bits.

  25. 25. What is the output of a Boolean OR gate when both of its inputs are 1?
    Show answer

    1, as either input or both at 1 gives 1

    In Boolean logic OR gives 1 when either input or both are 1, unlike the everyday ‘or’. A gate that gives 0 when both inputs are 1 is the exclusive OR (EOR).

  26. 26. For which pair of inputs does an exclusive OR (EOR) gate give a different output from an ordinary OR gate?
    Show answer

    A = 1, B = 1

    EOR is true only when exactly one input is true, so with both inputs at 1 it gives 0 while OR gives 1. For the other three pairs the two gates agree.

  27. 27. A two-input AND gate has four possible input pairs. For how many of them is its output 1?
    Show answer

    One

    AND gives 1 only when both inputs are 1, which is one pair out of 00, 01, 10 and 11. Three is the count for OR, which gives 1 when either input is 1.

  28. 28. What is a NAND gate?
    Show answer

    An AND gate followed by a NOT gate

    A NAND puts the output of an AND gate through a NOT, so its output is 0 only when all its inputs are 1. A NOT on just one input makes a different gate altogether.

  29. 29. For which pair of inputs is the output of a two-input NOR gate 1?
    Show answer

    A = 0, B = 0

    A NOR is an OR followed by an inverter: the OR gives 0 only when both inputs are 0, so the NOR gives 1 only then. Both inputs at 1 is the one pair that makes an AND give 1.

  30. 30. In the manual’s three-input example, D = NOT((NOT-A AND B) OR NOT-C) AND (A OR C). Which set of inputs makes D = 1?
    Show answer

    A = 1, B = 1, C = 1

    All at 1: NOT-A AND B = 0 and NOT-C = 0, so the NOR gives 1; A OR C = 1, so D = 1. With 0, 1, 1 the NOR gives 0; ignoring its circle gives a wrong D = 1.

  31. 31. What does the output of a combination logic circuit depend on?
    Show answer

    Only what its inputs are doing right now

    Combination logic simply works out its output from the inputs present now: if they stay constant, so does the output. A stored state and a clock belong to sequential logic.

  32. 32. What does a sequential logic circuit use to work out its new output?
    Show answer

    Its inputs and its past state, on a clock edge

    Sequential logic takes account of the past, such as earlier outputs held in latches, and works out the new output when the clock changes. Using only the present inputs is combination logic.

  33. 33. In the manual’s D flip-flop, when is the value at the Data input passed to the output?
    Show answer

    On the rising edge of the clock

    The rising edge of Clock copies Data to Output; if Data then changes, Output holds its value until the next rising edge. The Clear input is used at switch-on to force the output to 0.

  34. 34. What does the manual call the basic building blocks of memory in logic circuits?
    Show answer

    Latches

    Memory is built from latches, such as the D flip-flop; plain gates only combine their present inputs. Counters and shift registers are larger blocks made by joining flip-flops together.

  35. 35. In a logic diagram, what does a small circle drawn on a gate’s output show?
    Show answer

    The output is inverted

    The small circle stands for an inverter, so an OR gate with a circle on its output is a NOR. It has nothing to do with clocking or earthing.

  36. 36. By the Nyquist theorem, how often must a signal be sampled if it is to be reproduced faithfully?
    Show answer

    At least twice in every cycle of its highest frequency

    Nyquist requires at least two samples in each cycle, so a complex signal must be sampled at more than twice its highest frequency. One sample a cycle is too few: the samples then trace out a false, lower frequency.

  37. 37. Speech reaching up to 3,4 kHz is to be sampled. Which of these sampling rates is the only one that meets the Nyquist theorem?
    Show answer

    8 kHz

    The rate has to exceed twice the highest frequency, 2 × 3,4 = 6,8 kHz, so of these only 8 kHz will do; telephone systems use it. Sampling at 3,4 kHz gives just one sample per cycle.

  38. 38. A computer sound card samples at 44,1 kHz. Which of these is nearest to the highest signal frequency it can handle?
    Show answer

    20 kHz

    The limit is half the sampling rate, 44,1 ÷ 2 = 22,05 kHz, nearest 20 kHz, which is why such cards cover audio to 20 kHz. The manual’s example card samples at 42 kHz.

  39. 39. When a signal is sampled too slowly, the rebuilt signal is a sine wave of a different, lower frequency. What is that frequency called?
    Show answer

    An alias frequency

    The false, lower frequency left by too few samples per cycle is an alias, and the distortion is called aliasing. An image is something else: a superhet’s unwanted response, or a copy of a signal around a clock frequency.

  40. 40. What kind of filter is placed ahead of the sampling device to prevent aliasing?
    Show answer

    Lowpass or bandpass, to stop what is too high to sample

    A lowpass or bandpass anti-aliasing filter removes what the sampler cannot handle; a sound card’s filter stops signals above 20 kHz. A highpass filter would pass exactly the frequencies that cause aliasing.

    Try it: Low-pass Filter Designer
  41. 41. A 13 kHz tone reaches a sampler working at 10 kHz. At what frequency does it appear in the samples?
    Show answer

    3 kHz

    Samples taken at 10 kHz cannot tell 13 kHz from 13 − 10 = 3 kHz, so the tone appears at 3 kHz, below half the sampling rate. Taking away half the rate, to get 8 kHz, is a slip.

  42. 42. An ADC takes one sample every 12 µs. Which of these is nearest to its sampling rate?
    Show answer

    80 kHz

    Sampling rate = 1 ÷ period, and 1 ÷ 0,000 012 = 83 333 Hz, nearest 80 kHz. Half of that, about 42 kHz, is the highest frequency such a rate can carry, not the rate itself.

    Try it: Frequency ↔ Wavelength
  43. 43. How many levels can a 10-bit ADC resolve?
    Show answer

    1 024

    An n-bit converter resolves 2ⁿ levels: 2¹⁰ = 1 024. The answer 20 confuses 2ⁿ with 2 × n, and 512 is 2⁹, one bit short.

  44. 44. How many different values can a group of four bits hold?
    Show answer

    16

    Each extra bit doubles the count: 2⁴ = 16 values, 0000 to 1111. The highest of them is 15 (1111), one less than the number of values; 8 confuses 2⁴ with 2 × 4.

  45. 45. Which of these is nearest to the largest quantisation error of a good 8-bit ADC, as a share of its full scale?
    Show answer

    0,2 %

    An 8-bit ADC has 2⁸ = 256 levels and is out by at most half a step: 1 ÷ 512 = 0,001 95, about 0,195 %, nearest 0,2 %. Forgetting the half gives about 0,4 %.

  46. 46. What causes quantisation noise in a digitised signal?
    Show answer

    The ADC has only so many levels to choose from

    The ADC can report only whole levels, so each sample is slightly off the true voltage; these errors come out as quantisation noise. Timing errors are aperture jitter, a separate source of noise.

  47. 47. Each extra bit halves an ADC’s step size, halving the quantisation noise voltage. By about how many decibels does that lower the noise?
    Show answer

    6 dB

    A voltage ratio in decibels is 20 log₁₀ of the ratio, and 20 log₁₀ 2 = 6,02, so about 6 dB per bit. 3 dB is the figure for halving a power, not a voltage (chapter 12).

    Try it: dBm, Watts & dB
  48. 48. Why does the manual say that an ADC’s non-linearity matters most for small signals?
    Show answer

    An error of 1 or 2 steps is a big share of a small signal

    The error is about ±1 or 2 steps over the whole range: a trifle beside a strong signal using most of the levels, but a large share of a weak one. The error does not grow; its share does.

  49. 49. For each sample, what does an analogue-to-digital converter produce?
    Show answer

    A number in proportion to the input voltage

    For each sample the ADC gives a number directly proportional to the input voltage, as finely as its number of bits allows. Turning numbers back into voltages is the job of the DAC.

  50. 50. What is the difference between FIR and IIR digital filters?
    Show answer

    FIR uses present and past inputs; IIR also feeds back past outputs

    An FIR filter forms each output from the current input and earlier inputs only; an IIR filter also uses its own previous outputs, which is feedback. The swapped version is the usual slip.

  51. 51. Which digital filter type can become unstable if it is badly designed, and why?
    Show answer

    IIR, because it feeds earlier outputs back

    Feedback can make a loop oscillate (chapter 19), and only the IIR filter feeds results back; with no feedback an FIR filter is always stable. The manual names the feedback but leaves stability unsaid.

  52. 52. The manual calls one digital filter’s name something of a misnomer, since its response to a single pulse really dies away instead of lasting forever. Which filter?
    Show answer

    The IIR filter

    IIR stands for infinite impulse response, yet the response to one pulse shrinks until it falls below the processor’s resolution, so it is not truly infinite. An FIR filter’s response is finite by design.

  53. 53. A digital filter works out each output as 0,2 × (new input) + 0,8 × (previous output). The output starts at 0, then three input samples of 1 arrive in turn. Which is nearest to the output after the third of them?
    Show answer

    0,5

    The outputs are 0,2, then 0,2 + 0,8 × 0,2 = 0,36, then 0,2 + 0,8 × 0,36 = 0,488, nearest 0,5: a rise towards 1 like an RC circuit charging. Adding 0,2 each time, for 0,6, ignores the 0,8 factor.

  54. 54. The manual’s simplest IIR filter gives the same response as which analogue circuit?
    Show answer

    An RC lowpass filter

    Its output creeps towards each new input level in ever smaller steps, the same exponential curve as a capacitor charging through a resistor. A highpass filter would pass sudden changes and block steady levels.

  55. 55. Designing an FIR filter consists mainly of choosing its set of constant multipliers. What are these constants called?
    Show answer

    Coefficients, also known as tap weights

    The constants that multiply the stored samples are the FIR coefficients, also called tap weights. The delay elements only hold earlier samples until they are needed.

  56. 56. As with analogue filters, what does an FIR filter design trade against each other?
    Show answer

    Coefficient count, passband ripple and out-of-band rejection

    More coefficients buy less passband ripple and better rejection outside the passband, at the cost of more calculation, much as extra sections do in an LC filter. Clock speed and supply voltage are hardware matters.

  57. 57. A filter multiplies the three latest input samples, newest first, by 0,5; 0,3 and 0,2 and adds the results. The samples, newest first, are 10, 0 and 5. What is the output?
    Show answer

    6

    Output = 0,5 × 10 + 0,3 × 0 + 0,2 × 5 = 6, each constant paired with its own sample. Pairing them in the wrong order gives 0,5 × 5 + 0,2 × 10 = 4,5.

  58. 58. Which filter responses can an FIR filter give, by the manual?
    Show answer

    Any LC response, Butterworth and Chebyshev included

    The FIR structure can be highly selective and can match every response of LC filters, Butterworth and Chebyshev included. It is not limited to gentle slopes or to one filter type.

  59. 59. In the manual’s DSP block diagrams, what does a box marked DELAY do?
    Show answer

    Holds each sample back by one sample period

    The DELAY block passes each sample on one sample period later, building the store of earlier values a filter works with. A circle marked Σ adds its inputs and a circle marked X multiplies them.

  60. 60. In what order are the blocks of the manual’s digital bandpass filter connected, from input to output?
    Show answer

    A/D converter, DSP, D/A converter

    The analogue input is first turned into numbers by the A/D converter, the DSP filters those numbers by calculation, and the D/A converter turns the result back into a signal.

  61. 61. What does a DDS use to produce its output waveform?
    Show answer

    Sine values from a table, read out in turn by a clock

    For each new phase the DDS looks up the sine value in a lookup table and passes it to a DAC at every clock pulse. Multipliers and dividers belong to other ways of making frequencies (chapter 20).

  62. 62. Why is direct digital synthesis called ‘direct’?
    Show answer

    Its basic process uses no feedback loop

    Direct refers to the absence of feedback: each output value is worked out outright from the phase. A PLL synthesiser, by contrast, keeps its VCO locked with a negative-feedback loop (chapter 20).

  63. 63. A DDS has a 28-bit phase accumulator and a 50 MHz clock. Which of these is nearest to its smallest frequency step?
    Show answer

    0,19 Hz

    The step is the clock frequency divided by 2²⁸: 50 000 000 ÷ 268 435 456 = 0,186 Hz, nearest 0,19 Hz. Dividing by 2²⁷ instead doubles it to about 0,37 Hz.

  64. 64. A DDS with a 24-bit phase accumulator runs from a 100 MHz clock. Its frequency setting word is 2²⁰. What is its output frequency?
    Show answer

    6,25 MHz

    Output = word × clock ÷ 2²⁴, and 2²⁰ ÷ 2²⁴ is 1 ÷ 16, so 100 ÷ 16 = 6,25 MHz. Taking 2⁴ as 2 × 4 = 8 gives the wrong 12,5 MHz.

  65. 65. In a DDS, what is added to the phase register at every clock pulse?
    Show answer

    The frequency setting word, a fixed phase step

    Each clock pulse adds the frequency setting word to the phase register, so a bigger word steps round the cycle faster and gives a higher output frequency. Adding 360° would leave the phase unchanged.

  66. 66. A DDS runs from a 180 MHz clock. What is the highest output frequency it can usually produce?
    Show answer

    About 90 MHz

    The output is limited to about half the clock frequency, here 180 ÷ 2 = 90 MHz, and sometimes less, since each output cycle needs at least two clock samples. The clock frequency itself is out of reach.

  67. 67. Why must the output of a DDS be filtered before it is fed to a mixer?
    Show answer

    The DAC output comes in steps, making unwanted signals

    Because of quantisation the DAC output changes in steps, and the steps bring unwanted signals; a lowpass or bandpass filter removes most of them. A filter cannot raise a weak output.

    Try it: Low-pass Filter Designer
  68. 68. What happens in a DDS phase register when the phase reaches 360°?
    Show answer

    It rolls over and carries on counting from 0°

    Phase returns to 0 after 360°, so the register simply rolls over and keeps counting, like a car’s odometer. Stopping or reversing would break the smooth run of sine values.

  69. 69. What gives a DDS its very high frequency stability?
    Show answer

    A clock taken from a crystal oscillator

    The DDS output is only as stable as its clock, which is usually derived from a crystal oscillator, so it is very stable and finely settable. A sharp filter cleans up the output but does not hold its frequency.

  70. 70. What is the fast Fourier transform (FFT) used for?
    Show answer

    Calculating a sampled signal’s frequencies efficiently

    The FFT is an efficient way of calculating which frequencies a block of samples contains, cutting the work of the direct method. It calculates rather than measures, and needs no analogue filters.

  71. 71. Fourier first devised his transform for continuous signals. Which variant is used for sampled signals?
    Show answer

    The discrete Fourier transform, or DFT

    For sampled signals DSP uses the discrete Fourier transform, which takes a block of N samples and shows which sine frequencies it contains. The FFT is simply a fast way of computing it.

  72. 72. Which of these is nearest to the number of complex multiplications needed to work out a 512-point Fourier transform the direct way?
    Show answer

    250 000

    The direct method needs N multiplications for each of N output frequencies, so 512 × 512 = 262 144, nearest 250 000. Adding instead, 512 + 512 = 1 024, is the slip; the FFT exists to cut this work.

  73. 73. What problem does windowing tackle when signals are analysed in blocks of samples?
    Show answer

    The sharp jumps at the two ends of each block

    Cutting a signal into blocks leaves discontinuities at each end, which add unexpected spectral components; a window function tapers them away. No samples go missing between blocks; the trouble is the abrupt edges.

  74. 74. Besides windowing, what other way of easing block-edge effects does the manual mention, and what is its drawback?
    Show answer

    More output frequencies, though results are harder to allocate

    Using more discrete output frequencies eases the edge effects, but it complicates deciding which output frequency a result belongs to. Windowing, which tapers the block, avoids that difficulty.

  75. 75. Which window function is the same as using no window at all?
    Show answer

    The rectangular window

    A rectangular window leaves every sample of the block unchanged, so using it is the same as using none. The triangular, Blackman, Hamming and Hanning windows all shape the block.

  76. 76. The spectra of the common window functions look like the response of which kind of filter?
    Show answer

    A lowpass filter

    The manual notes that window spectra resemble lowpass responses, so windows are a common starting point when lowpass filters are designed. They do not look like highpass or bandstop shapes.

  77. 77. What does the manual say convolution can be used for?
    Show answer

    Finding a filter’s output without an FFT and inverse FFT

    Convolving the input with the network’s impulse response gives the output directly, which can be simpler than FFT, multiply and inverse FFT. Finding a spectrum is the FFT’s job, not convolution’s.

  78. 78. Convolution in the time domain is the equivalent of which operation in the frequency domain?
    Show answer

    Multiplication

    Multiplying the input spectrum by the network’s frequency response gives the output spectrum; convolving the input with the network’s impulse response does the same job in the time domain.

  79. 79. To find a network’s output signal in the time domain, the input signal is convolved with what?
    Show answer

    The network’s own impulse response

    In the time domain the input is convolved with the impulse response; the frequency response is what the input spectrum is multiplied by in the frequency domain. Mixing up the two domains is the slip.

  80. 80. Convolution works out one signal from two others. Which version of the second signal does it compare the first with?
    Show answer

    A time-reversed version

    The manual describes convolution as comparing one signal with a time-inverted copy of the other. Shifting a signal in frequency is the job of a mixer.

  81. 81. What is a software-defined radio (SDR), as the manual describes it?
    Show answer

    A generic radio whose functions are all carried out in software

    An SDR is a generic radio with minimal analogue parts, simple ADC and DAC circuits and a powerful DSP doing the real work in software. Working an ordinary radio from a PC does not make it an SDR.

  82. 82. Which free platform does the manual describe for experimenting with SDR?
    Show answer

    Linrad

    Linrad is free to download, runs under Linux without licence or copyright restrictions and suits experiments on old computers. Linux is the operating system it runs on, not the SDR platform itself.

  83. 83. What kind of computer does Linrad need, by the manual?
    Show answer

    Nothing elaborate: even an obsolete one will do

    Linrad needs no elaborate hardware and runs on obsolete previous-generation computers, which keeps experimenting cheap. A fast modern machine is not needed.

  84. 84. Some VHF radio makers keep only one model in stock for all their customers. How does each user get what they need?
    Show answer

    Each set is programmed for that user’s modes and channels

    The same generic radio is programmed with each user’s modulation mode, channels and tone combinations, so one stock item serves everyone. A plug-in board would be the physical change that programming avoids.